Let 
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are
where 
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if 
, and we know that this happens after two hours, i.e. at 
Solving this equation for v we have
So, train A is travelling at 105 km/h. This implies that train B travels at
130 degrees.
ADB = 90 degrees
BDT=40 Degrees
Therefore, TDS = ADB(90)+BDT(40)=130 degrees
You could make them have the same denominator, making it 7/10-5/10=2/10.
The answer is 2/10, or simplified, 1/5.
Step-by-step explanation:
Z = 2x + 3
Putting value of x
Z = 2( - 16.7) + 3
Z = - 33.4 + 3
Z= - 30.4
Option B is the correct answer
Answer:
31
Step-by-step explanation:
(-1-2)^2+(-5-1)^2
(1+4)+(25+1)
5+26
31
