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3 years ago

What is the probability of living another year for a woman who is 73 years old ?

Mathematics

1 answer:

AlladinOne [14]3 years ago

8 0

Answer:

0.980413

Step-by-step explanation:

The table for the deaths and death rate per 100,000 population is attached below ;

73 years fall in the 65 - 74 years category ; with 1958.7 deaths (Female)

Hence, the probability of living another year is :

Number of deaths per 100,000 population ;

P(death) = 1958.7 / 100,000 = 0.019587

Probability of living another year = 1 - P(death)

1 - 0.019587 = 0.980413

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Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

PLEASE HELP ASAP

7nadin3 [17]

<u>Answer</u>

√7 × √5

√3 × √2

<u>Explanation</u>

√9*√16 = 3 × 4

= 12

= 12/1 ⇒ It is a rational answer.

√7*√5 = √(7×5)

= √35

= 5.916079783.... ⇒ Irrational

√3*√2 = √(3×2)

= √6

= 2.449489743... ⇒ Irrational

4√2*√2 = 4 × √(2×2)

= 4 × √4

= 4 × 2

= 8

= 8/1 ⇒ It is rational

The expressions that would give irrational answers are: √7*√5 and√3*√2

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