Ask question

Ask question

All categories

Oksi-84 [34.3K]

3 years ago

12

Katie bought 4 sweaters that each cost the same amount and 1 skirt that cost $20. the items she bought cost a total of 160$. wri

te an equation to determine each cost of each sweater.

1 answer:

Rufina [12.5K]3 years ago

4 0

Answer:

160-20=140. 140/4=$35.

You might be interested in

Please need the answer

zvonat [6]

Answer:

A. True

B. True

C. False

Step-by-step explanation:

Hope that helps!

3 0

3 years ago

What is the inverse of the function f(x) = x +3?

MAXImum [283]

Answer:

f⁻¹(x) = x - 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

Functions
Function Notation
Inverse Functions

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = x + 3

<u>Step 2: Find</u>

Swap: x = y + 3
[Subtraction Property of Equality] Isolate <em>y</em>: x - 3 = y
Rewrite: f⁻¹(x) = x - 3

6 0

3 years ago

Find the surface area of the prism and I also need the one underneath.

WINSTONCH [101]

Answer:

c) 1872m^2

Question4: 992m^2

Step-by-step explanation:

4 0

3 years ago

Rectangle A′B′C′D′ is the image of rectangle ABCD after a dilation centered at point P.

liraira [26]

Answer:

-5/6

Step-by-step explanation

Just took the test

4 0

2 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given points. (x2 + y2)2 = 3x2y − y3;

Andrew [12]

Answer:

a. $y+1=0$

b. $2x+4y=1$

Step-by-step explanation:

We are given that

$(x^2+y^2)^2=3x^2y-y^3$

a.(0,-1)

Differentiate w.r.t x

$2(x^2+y^2)(2x+2yy')=6xy+3x^2y'-3y^2y'$ .....(1)

Substitute x=0 and y=-1 in equation (1)

$2(0+1)(-2y')=-3y'$

$-4y'+3y'=0$

$-y'=0$

$y'=0$

$m=y'=0$

Point-slope form:

$y-y_0=m(x-x_0)$

Using the formula

$y+1=0$

This is required equation of tangent line to the given curve at point (0,-1).

b.(-1/2,1/2)

Substitute the value in equation (1)

$2(1/4+1/4)(-1+y')=6(-1/2)(1/2)+3(1/4)y'-3(1/4)y'$

$2(2/4)(-1+y')=-3/2+3/4y'-3/4y'$

$-1+y'=-3/2$

$y'=-3/2+1=\frac{-3+2}{2}=-\frac{1}{2}$

$m=y'=-1/2$

Again using point-slope formula

$y-1/2=-1/2(x+1/2)$

$\frac{2y-1}{2}=-\frac{1}{4}(2x+1)$

$2y-1=-\frac{1}{2}(2x+1)$

$4y-2=-2x-1$

$2x+4y=2-1$

$2x+4y=1$

5 0

3 years ago