Answer:
The speed of the car at the end of the 2nd second = 8.0 m/s
Explanation:
The equations of motion will be used to solve this problem.
A car starts from rest,
u = initial velocity of the car = 0 m/s
Accelerates at a constant rate in a straight line,
a = constant acceleration of the car = ?
In the first second the car moves a distance of 2.0 meters,
t = 1.0 s
x = distance covered = 2.0 m
x = ut + (1/2)at²
2 = 0 + (1/2)(a)(1²)
a = 4.0 m/s²
How fast will the car be moving at the end of the second second
Now,
a = 4.0 m/s²
u = initial velocity of the car at 0 seconds = 0 m/s
v = final velocity of the car at the end of the 2nd second = ?
t = 2.0 s
v = u + at
v = 0 + (4×2)
v = 8.0 m/s
To calculate the horizontal velocity component, use the cosine identity. where cos A = a / h
where A is the angle the golfer hits the ball
a is the horizontal component velocity
h is the speed the golfer hits the ball
so a = h cos A
a = 31 cos 35
a = 25.4 m/s
This belongs in the bio section but the structure are the chromosomes that contain the DNA strands themselves containing the genetic information of any living things
The answer is C. 15 meters North
Displacement is the distance and direction from the origin. If you move 20 meters North, your displacement is 20 meters North. If you move 5 meters South, you are basically moving back the way you came by 5 meters, which means you are now 15 meters North.
I hope this helped! :)
