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2 years ago

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Across a horizontal distance of 25 feet, a roller coaster has a steep drop. The height of the roller coaster at the bottom of th

e drop is -125 feet, compared to its height at the top of the drop. What is the average amount that the roller coaster's height changes over each horizontal foot?

2 answers:

allsm [11]2 years ago

6 0

X = total horizontal distance = 25 ft

Y = total vertical distance = 125 ft

x = horizontal distance = 1 ft

y = vertical distance = ?

using the equation

y = (Y/X) (x)

inserting the values

y = (125/25) (1)

y = 5 ft

hence for each horizontal foot, the average height change is 5 ft

or

25 ft horizontal distance traveled = 125 ft vertical distance dropped

dividing both side by 25

25 ft horizontal distance traveled/25 = 125 ft vertical distance dropped/25

1 foot horizontal distance traveled = 25 ft vertical distance dropped

hoa [83]2 years ago

4 0

Answer: -5

Explanation: You correctly divided the absolute values, but since you are dividing a negative height by a positive number of horizontal feet, the answer is negative. What the hell I thought this answer was supposed to be verified....By who the same person that gave the wrong answer?????

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Answer:

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c)34.33m/S

d)44.66m/S

Explanation:

Hello!

we will solve this exercise numeral by numeral

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T = time

g=gravity=9.81m/s^2

y = height=60m

solving for time

$Y=0.5gt^2\\t=\sqrt{\frac{Y}{0.5g} } \\t=\frac{60}{0.5(9.81)} \\$

T=3.5s

b)The horizontal speed remains constant since there is no horizontal acceleration. with the value of the distance traveled (100m) and the time that lasts in the air (3.5s) we estimate the horizontal speed

$V=\frac{x}{t} =\frac{100}{3.5}=28.57m/s$

c)

to find the final vertical velocity we use the equations for motion with constant velocity as follows

Vf=Vo+g.t

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2 years ago

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3 years ago

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BigorU [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

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b

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From the question we are told that

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n200080 [17]

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