20. I am a noble gas with 2 electrons.

A 3.20 g sample of a salt dissolves in 9.10 g of water to give a saturated solution at 25°C. a. What is the solubility (in g sal

muminat

Answer:

The solubility of the salt is 35.16 (g/100 g of water).

It would take 71.09 grams of water to dissolve 25 grams of salt.

The percentage of salt that dissolves is 52.7 %

Explanation:

We know that 3.20 grams of salt in 9.10 grams of water gives us a saturated solution at 25°C. To find how many grams of salt will gives us a saturated solution in 100 grams of water at the same temperature, we can use the rule of three.

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{x \ g \ salt}{100 \ g \ water}$

Working it a little this gives us :

$x = 100 \ g \ water * \frac{3.20 \g \ salt}{9.10 \ g \ water}$

$x = 35.16 \ g \ salt$

So, the solubility of the salt is 35.16 (g/100 g of water).

Using the rule of three, we got:

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{25 \ g \ salt}{x \ g \ water}$

Working it a little this gives us :

$x = \frac{25 \ g \ salt}{ \frac{3.20 \g \ salt}{9.10 \ g \ water}}$

$x = 71.09 g \ water$

So, it would take 71.09 grams of water to dissolve 25 grams of salt.

Using the rule of three, we got that for 15.0 grams of water the salt dissolved will be:

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{x \ g \ salt}{15.0 \ g \ water}$

Working it a little this gives us :

$x = 15.0 \ g \ water * \frac{3.20 \g \ salt}{9.10 \ g \ water}$

$x = 5.27\ g \ salt$

This is the salt dissolved

The percentage of salt dissolved is:

$percentage \ salt \ dissolved = 100 \% * \frac{g \ salt \ dissolved}{g \ salt}$

$percentage \ salt \ dissolved = 100 \% * \frac{ 5.27\ g \ salt }{ 10.0 \ g \ salt}$

$percentage \ salt \ dissolved = 52.7 \%$

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sattari [20]

Answer:

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Explanation:

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geniusboy [140]

Answer:

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Explanation:

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olga2289 [7]

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