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2 years ago

6

Expand 8(x-5) I really need the answer!!

2 answers:

erastovalidia [21]2 years ago

7 0

Answer:

8x-40

Step-by-step explanation:

im not too sure what answer you're liking for here so 8•x is 8x and 8x5 is 40

SVETLANKA909090 [29]2 years ago

3 0

8(x-5)

multiply the bracket by 8

(8)(x)=8x

(8)(-5)=-40

answer:

8x-40

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Will mark brainliest.

xeze [42]

Answer:

Area=7.7*2=15.4m²

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3 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

GuDViN [60]

Answer:

Euler's method is a numerical method used in calculus to approximate a particular solution of a differential equation. As a numerical method, we have to apply the same procedure many times, until get the desired result.

In first place, we need to know all the values the problem is giving:

The step size is 0.2; h = 0.2. This step size is a periodical increase of the x-variable, which will allow us to calculate each y-value to each x.
The problem is asking the solution y(1), which means that we have to find the y-value assigned for x = 1, through the numerical method.
The initial condition is y(0) = 9. In other words, $x_{o} = 0\\y_{0}=9$ .

So, if the initial x-value is 0, and the step size is 0.2, the following x-value would be: $x_{1}=0.2$ ; then $x_{2}=0.4$ ; $x_{3} =0.6; x_{4} =0.8;x_{5} =1$ ; and so on.

Now, we have to apply the formula to find each y-value until get the match of $x_{5}=1$ , because the problem asks the solution y(1).

According to the Euler's method:

$y_{1} =y_{0} +hF(x_{0};y_{0})\\y_{2} =y_{1} +hF(x_{1};y_{1})\\y_{n} =y_{n-1} +hF(x_{n-1};y_{n-1})$

Where $F(x;y)=x^{2} y-12y^{2}$ , and $x_{0} =0; y_{0} =9$ ; $h=0.2$ .

Replacing all values we calculate the y-value assigned to $x_{1}$ :

$y_{1} =9+0.2((0)^{2} 9-12(9)^{2})=-185.4$ .

Now, $y_{1} =-185.4$ , $x_{1} =0.2; h=0.2$ . We repeat the process with the new values:

$y_{2} =y_{1} +hF(x_{1};y_{1}) \\y_{2} = -185.4+0.2((0.2)^{2} (-185.4)-12(-185.4)^{2} )\\y_{2}=-82682.47$

Then, we repeat the same process until get the y-value for $x_{5} =1$ , which is $y_{5} = -1.0018$ , round to four decimal places.

Therefore, $y(1)=-1.0018$ .

7 0

3 years ago

Help please anybody

Sedbober [7]

put in an positive number for x and check

2 - 5 = -3

5 - 2 = 3

- 2 + 5 = 3

5 + (-2) = 2

so the only different one is the first

4 0

3 years ago

For all values of x,<br>f(x) = x^2 + 3x and g(x) = x - 4<br>Show that fg(x) = x^2 - 5x + 4

Westkost [7]

Answer:

f(g(x)) = x² - 5x +4

Step-by-step explanation:

<u><em>Explanation</em></u>

Given that the functions

f(x) = x² + 3 x and g(x) = x-4

f(g(x)) = f(x -4) (∵ g(x) = x-4)

= (x-4)² + 3(x-4)

= x² - 2(4)x + 4² + 3x -12

= x² - 8 x + 16 + 3x -12

= x² - 5x +4

∴ f(g(x)) = x² - 5x +4

4 0

3 years ago

Find the distance between the points given. (-3, 2) and (9, -3) A √37 B √61 C 13

Kitty [74]

Answer:

$\huge{ \fbox{ \sf{13 \: units}}}$

Option C is correct.

Step-by-step explanation:

$\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}$

$\star{ \sf{ \: let \: A(-3, 2) \: be \: (x1 \:, y1) \: and \: B(9, -3) \: be \: (x2 \:, y2) }}$

$\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{ \sqrt{ {(9 - ( - 3))}^{2} + {( - 3 - 2)}^{2} } }}$

$\mapsto{ \sf{ \sqrt{ {(9 + 3)}^{2} + {( - 3 - 2)}^{2} }}}$

$\mapsto{ \sf{ \sqrt{ {(12)}^{2} + {( - 5)}^{2} } }}$

$\mapsto{ \sf{ \sqrt{144 + 25}}}$

$\mapsto{ \sf{ \sqrt{169} }}$

$\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}$

$\mapsto{ \sf{ 13 \: units}}$

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

7 0

2 years ago