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Zolol [24]
2 years ago
12

Water in a 14mm diameter pipe flows at 2m/s. How many liters flow along the pipe in 1 minute

Mathematics
1 answer:
Over [174]2 years ago
6 0

Answer:

The flow rate will be say around 10000 liters per hour. Or 180 liters per minute.

Step-by-step explanation:

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What is the area of the following parallelogram in square centimeters?
Scrat [10]

Answer:

3.6 cm²

Step-by-step explanation:

18 mm = 1.8 cm

A = 2cm×1.8cm = 3.6 cm²

7 0
3 years ago
Read 2 more answers
a trapezoid has base lengths of 6 and 15 centimeters with an area of 136.5 square centimeters. What is the height of the trapezo
MrRa [10]
•*Ok first let me show you the formula for the Area of the trapezoid.
A=a+b/2 h.(I will be using the letter x for the multiplication sign)
 
*And here is the formula to find the height of a trapezoid
h=2 x A/a+b (2 times the Area over base "a" plus base "b")


*We need to plug in the numbers: h = 2 x 136.5/6+15
*Next, we add the two bases to get 21: 6+15=21 (h=2 x 136.5)  
*Then, divide the total of the two bases (21) from the area to get 6.5: 136.5/21-6.5
*Finally we multiply 2 by 6.5: 2 x 6.5= 13
The height if this trapezoid is 13.

Hope this helps you ☺
3 0
3 years ago
Solve the system of equations.<br> 57 - 10x = 45<br> -<br> - 3y + 10x = -5
masha68 [24]

Answer: Step-by-step explanation:

57 - 10x = 45

-10x=-12

x=1.2

- 3y + 10x = -5

-3y+10=-5

-3y=-15

y=5

7 0
3 years ago
Read 2 more answers
On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
swat32

Check the picture below.

since the vertical distance, namely the y-coordinate, is twice as much as the horizontal, then if the horizontal is "x", the vertical one must be 2x.

let's find the hypotenuse first.

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{x}\\ b=\stackrel{opposite}{2x}\\ \end{cases} \\\\\\ c=\sqrt{x^2+(2x)^2}\implies c=\sqrt{x^2+4x^2}\implies c=\sqrt{5x^2}\implies c=x\sqrt{5} \\\\[-0.35em] ~\dotfill

\bf sin(\theta )=\cfrac{\stackrel{opposite}{2~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}{\stackrel{hypotenuse}{~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \sqrt{5}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \cfrac{2\sqrt{5}}{5}}

5 0
3 years ago
Solve 5n -14≤11 <br>*10 points*​
Sedbober [7]

Answer:

n ≤ 5

Step-by-step explanation:

First, we add 14 to both sides. This gets us 5n ≤ 25. Next, we divide both sides by 5. This gets us n ≤ 5. I hope this helps!

4 0
2 years ago
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