The solution to the system of equation are x = -2 and y = 3
<h3>How to find the solution of a system of equation?</h3>
x + 3y = 7
2x + 4y = 8
Let's isolate x in the first equation
x = 7 - 3y
substitute the value of x in the second equation.
Therefore,
2(7 - 3y) + 4y = 8
14 - 6y + 4y = 8
-2y = 8 - 14
-2y = -6
y = -6 / -2
y = 3
Hence,
x + 3(3) = 7
x = 7 - 9
x = -2
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-9x-6y=15
9x-10y=145
Find y first by eliminating the x.
Add the two equations together.
-9x+9x-6y+-10y=15+145
-6y+-10y=15+145
-6y-10y=160
-16y=160
divide both sides by -16 to get +y
-16y/-16=160/-16
y=-10
Use the substitution method to find x
-9x-6y=15
-9x-6(-10)=15
Do the bracket first
-9x+60=15
Move +60 to the other side. Sign changes from +60 to -60.
-9x+60-60=15-60
-9x=-45
Divide both sides by -9
-9x/-9=-45/-9
x=5
Answer:
( 5,-10)
∠BCD = 57°
∴ ∠BDR = ∠BCD = 57° (angle that meets the chord and the tangent is equi-angular to the angle at the alternate segment)
Answer:
22
Step-by-step explanation:
The preimeter is adding all sides together. I took 154-55 twice sense we have four sides of a rectangle and two are lengths. after that i got 44. I then just remembered we had two sides left so divided that by 2 and got 22