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3 years ago

AM I CUTE? TELL ME IM CUTE !!! whats the square root of 5?

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

Answer:

nah

Step-by-step explanation:

bshsybejsisihsshsjuxgsjaizgsjsks

algol [13]3 years ago

3 0

Answer:

Yes you are a lot, even if people say no. Also the answer is 2.23

Step-by-step explanation:

You might be interested in

What is the location of the point on the number line that is 3/7 of the way from A=6 to B=20?

-Dominant- [34]

Answer:

Step-by-step explanation:

20-6=14 (Distance between points) then 14*3/7=6.

3/7 of the distance from A=6 to B=20 is 6. Thus, we find the point that is

3/7 of the distance from A=6 to B=20 by adding 6 to 6.

6+6= 12

Therefore, the point that is

3/7 from A=6 to B=20 is 12.

7 0

3 years ago

Kelly is making greeting cards, which she will sell by the box at an arts fair. She paid $20 for

soldier1979 [14.2K]

Answer:

the materials to make the cards:)

Step-by-step explanation:

4 0

3 years ago

Larry spent 1/2 of his money on a camera and another 1/8 on a radio. the camera cost $120 more than the radio. how much money di

elena-s [515]

Let, his original money = x
It would be: x * 1/2 = 120
x = 120 * 2
x = 240

In short, Your Answer would be $240

Hope this helps!

7 0

3 years ago

Read 2 more answers

Select the correct answer. What is the opposite of ? A. B. C. D. E.

Helga [31]

Answer: what are the options?

Step-by-step explanation:

7 0

3 years ago

Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]

JulijaS [17]

Answer:

$f_{avg}=\frac{1}{e-1}$

Step-by-step explanation:

We are given that a function

$f(x)=2lnx$

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx$

By Parts integration formula

$\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx$

u=ln x and v=dx

Apply by parts integration

$f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))$

$f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})$

$f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}$

By using property lne=1,ln 1=0

$f_{avg}=\frac{1}{e-1}$

8 0

3 years ago