Answer:
Step-by-step explanation:
∛-64 = -4
![\sqrt[3]{m^{15}} =m^5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E%7B15%7D%7D%20%3Dm%5E5)
∛n³ = <em>n</em>
The answer is B(11, 2sqrt(12) )
proof
the main equation of the circle is (x-x1)²+(y-y1)²=R²
where C(x1, y1) is the center
so if the center is the origin, it is O(0,0), and the equation becomes
<span> (x)²+(y)²=R²
</span>and the circle passes through the point (-5,2) so we can write
(-5)²+12²=R², it implies R= sqrt(25+144)=sqrt(169)=13
and for <span>B(11, 2sqrt(12) ) </span>11²+ (2sqrt(12))²= 121 + 48= 169= 13
it is checked.
Answer:
Option C
Step-by-step explanation:
from the graph: y<4
so option A and B are wrong.
also if we choose any points in the area, always x will be bigger than y. so x>y
Neither the see attachments:
