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anastassius [24]
3 years ago
5

Please help it due ASAP Show workings!

Mathematics
1 answer:
kiruha [24]3 years ago
7 0

Answers:

AQ = 8

QD = 4

========================================================

Explanation:

A median goes from a vertex to the midpoint of the opposite side. The medians of this triangle are segments AD, BE, and CF.

The three medians intersect at the centroid. The centroid cuts the median AD such that

  • AQ is 2/3 as long as AD
  • QD is 1/3 as long as AD

Note how 2/3+1/3 = 3/3 = 1

Since AD = 12, we know that

  • AQ = (2/3)*AD = (2/3)*12 = 8
  • QD = (1/3)*AD = (1/3)*12 = 4

As a check,

AQ+QD = 8+4 = 12 = AD

So AQ+QD = AD is a true equation.

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What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
telo118 [61]

Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


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We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









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3 years ago
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Answer:

oa

Step-by-step explanation:

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