Answer:
7.64% probability that they spend less than $160 on back-to-college electronics
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Probability that they spend less than $160 on back-to-college electronics
This is the pvalue of Z when X = 160. So
has a pvalue of 0.0763
7.64% probability that they spend less than $160 on back-to-college electronics
<span>150% to decimal = 1.50 since 100% = 1
</span><span>1.50 x 20 = 30
</span><span>30 + 20 = 50</span>
Answer:
2.96
Explanation:
37/x=100/8
(37/x)*x=(100/8)*x - we multiply both sides of the equation by x
37=12.5*x - we divide both sides of the equation by (12.5) to get x
37/12.5=x
2.96=x
x=2.96
Answer:
V=1,244.071
Step-by-step explanation:
I put the answer in decimal form and rounded up from .0706, but pi form in included in the pic. I hope this helped! Please leave Brainliest if it did and is right.