The medians $AD$, $BE$, and $CF$ of triangle $ABC$ intersect at the centroid $G$. The line through $G$ that is parallel to $BC$ intersects $AB$ and $AC$ at $M$ and $N$, respectively. If the area of triangle $ABC$ is 144, then find the area of triangle $ENG$.
1 answer:
G divides each median in the ratio of 2 to 1 (the longer side goes from G to the angle)
triangle AMN is similar to triangle ABC (why?)
AMN is a scaled version of ABC (by a factor of ⅔)
its area should be scaled by (⅔)^2
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Answer:
no mistakes
Step-by-step explanation:
4 * 3^x = 324
Divide each side by 4
4/4 * 3^x = 324/4
3^x = 81
Rewriting 81 as a power of 3
3^x = 3^4
Since the bases are the same, the powers are the same
x=4
Answer:
y = 1/4 = 0.250.
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
You have to do base x height divided by 2
50/2
Y=-3x+10 follows the format of linear functions which is y=mx+b
Answer:
last one
Step-by-step explanation:
the first one doesn't have any solution, the second one has infinite solutions.