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zepelin [54]
4 years ago
12

(02.02 LC)

Mathematics
2 answers:
Katyanochek1 [597]4 years ago
7 0
The figure was simply rotated, the relative side lengths have not changed.

Length AB=Length A'B'
Elza [17]4 years ago
5 0
Length of AB=Length of A'B' because they are corresponding sides.
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The coefficient of x^2 in the expansion of (1+2x)^n is 60. given that n>0, find the value of n.​
Nitella [24]

<u>n=6</u>

Answer:

Solution given:

The coefficient of x^2=60

we have,

(a+x)^n=C(n,0)a^n+C(n,1)a^(n-1)x+C(n,2)a^(n-2)x^2+C(n,3)a^(n-3)x^3....C(n,r)a^(n-r)x^r+C(n,n)x^n

we get x² in 3rd term,so

3rd term of  (1+2x)^n is C(n,2)*1^n-2)(2x)^2=C(n,2)4x²

since 1^n is 1.

we have a coefficient of x^2 is 60, so

C(n,2)4=60

C(n,2)=60/4

\frac{n!}{(n-2)!*2!}=15

\frac{n(n-1)(n-2)!}{(n-2)!*2!}=15

n(n-1)=15*2

n^2-n=30

n^2-n-30=0

doing middle term factorization

n^2-6x+5x-30=0

n(n-6)+5(n-6)=0

(n-6)(n+5)=0

either n-6=0

n=6

or,

n+5=0

n=-5 since n>0

so neglected.

<u>So the value of n is 6.</u>

Step-by-step explanation:

8 0
2 years ago
Can you guys please help me?
Lina20 [59]

Answer:

I dont do graphs anymore that is 9th grade stuff B)))

Step-by-step explanation:

6 0
3 years ago
The ordered pairs (3,2) and (-2,13) are points on a linear function. Which equation best describes this function?
Mars2501 [29]

Answer:

The equation which describe this function is 5x + 11y = 37

Step-by-step explanation:

<u>To find the slope</u>

slope = (y₂ - y₁)/(x₂ - x₁)

slope = (13 - 2)/(-2 - 3) = 11/-5

<u>To find the equation</u>

(x - 3)/(y - 2) = -11/5

5(x - 3) = -11(y - 2)

5x -15  = -11y + 22

5x + 11y = 22 + 15

5x + 11y = 37

Therefore the equation which describe this function is

5x + 11y = 37

7 0
4 years ago
Read 2 more answers
Write all the factors of 27.<br> Use commas to separate them.
UkoKoshka [18]

Answer:

1,3,9,27

Step-by-step explanation:

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3 years ago
You attend a karaoke night and hope to hear your favorite song. The karaoke song book has 900 different songs (your favorite son
Afina-wow [57]
20/900
I not sure though
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