Answer with Step-by-step explanation:
We are given that
Total dogs=24
Total cats=18
Total animals=24+18=42
Male dogs=8
Male cats=6
Total male animals=8+6=14
Total female animals=42-14=28
Female cats=18-6=12
Dogs female=24-8=16
a.We have to find the probability that the pet is male, given that it is cat.
It means we have to find P(Male/cat)
Conditional probability: 
P(Cat)=
P(male/cat)=
b.
c.P(Dog)=
Answer:
-10
Step-by-step explanation:
when you subract a negative the minus signs negate each other
Complete question :
Cheddar Cheese
$3/lb
Swiss Cheese
$5/lb
Keisha is catering a luncheon. She has $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar cheese? Only Swiss cheese? A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Answer:
10 lbs of cheddar cheese
6 lbs of Swiss cheese
$3a + $5b = $30
Step-by-step explanation:
Given that :
Cheddar cheese = $3/lb
Swiss cheese = $5/lb
Total amount budgeted for cheese = $30
How many pounds of cheese can Keisha get if she buys only Cheddar cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of cheddar cheese
$30 / 3 = 10 pounds of cheedar cheese
Only Swiss cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of Swiss cheese
$30 / 5 = 6 pounds of Swiss cheese
A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Let amount of cheddar cheese she can get = a
Let amount of Swiss cheese she can get = b
Hence,
(Cost per pound of cheddar cheese * number of pounds of cheddar) + (Cost per pound of Swiss cheese * number of pounds of Swiss cheese) = total budgeted amount
(3 * a) + (5 * b) = $30
$3a + $5b = $30
1) $450/12=$37.50
2)$37.50x3=$112.50
The answer is: $112.50
I hope this helps
Rational it stops and repeats
