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3 years ago

Solve each system by substitution

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

8 0

Answer:

x = 0, y = -5

Step-by-step explanation:

you're given two equations:

y = 4x - 5

y = 2x - 5

to solve, just substitute y in the second equation.

y = 2x - 5

4x - 5 = 2x - 5

now that you have this, solve for x.

4x - 5 = 2x - 5

subtract 2x from both sides

4x - 5 - 2x = 2x - 5 - 2x

2x - 5 = -5

add 5 to both sides

2x - 5 + 5 = - 5 + 5

2x = 0

divide both sides by 2

2x/2 = 0/2

x = 0

now that you know x, substitute x for 0 in the second equation.

y = 2x - 5

y = 2 * 0 - 5

y = 0 - 5

y = - 5

anyanavicka [17]3 years ago

7 0

Answer:

equalize the both sides of the functions

Step-by-step explanation:

4x-5 = 2x-5

4x = 2x

2x = x

2 = 1 meaning phi

there is no answer for this problem

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Step-by-step explanation:

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3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

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Nimfa-mama [501]

Answer:

d is the answer

Step-by-step explanation:

just read the statements properly

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