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Ivanshal [37]
3 years ago
15

Solve each system by substitution

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer:

x = 0, y = -5

Step-by-step explanation:

<em>you're given two equations:</em>

y = 4x - 5

y = 2x - 5

<em>to solve, just substitute y in the second equation.</em>

y = 2x - 5

4x - 5 = 2x - 5

<em>now that you have this, solve for x. </em>

4x - 5 = 2x - 5

<em>subtract 2x from both sides</em>

4x - 5 - 2x = 2x - 5 - 2x

2x - 5 = -5

<em>add 5 to both sides</em>

2x - 5 + 5 = - 5 + 5

2x = 0

<em>divide both sides by 2</em>

2x/2 = 0/2

x = 0

<em>now that you know x, substitute x for 0 in the second equation.</em>

y = 2x - 5

y = 2 * 0 - 5

y = 0 - 5

y = - 5

anyanavicka [17]3 years ago
7 0

Answer:

equalize the both sides of the functions

Step-by-step explanation:

4x-5 = 2x-5

4x = 2x

2x = x

2 = 1 meaning phi

there is no answer for this problem

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You roll one die 8 times. What is the probability of rolling exactly six fours
julia-pushkina [17]

Answer:

4/8 = 1/2 = 0.5 is your answer

5 0
2 years ago
Nine less than six times a number is -15
Jlenok [28]

Hello!

6 - 9 × y = -15

When "less than" is used you switch the number before it the number after it. While it seems like it would be 9 -6, its actually 6-9

6 - 9 is -3, you can multiply 3 by 5, to get 15. So your answer would be 5

Hope this helps!

Please consider Brainliest!

8 0
3 years ago
The area of this rectangle is given by the quadratic function
Sonja [21]

<em>The function uses W as the variable but the options show only x's as the variable, so I'm asumming W in the answer</em>

Answer:

0 < W < 50

Correct option: A

Step-by-step explanation:

<u>Domain of functions</u>

Some functions have restricted values of the independent variable x. It can be due to mathematical restrictions, like dividing by 0 or taking the square root of a negative number, of it can be due to practical conditions of the situation being modeled.

In this case, the area of a rectangle is given by the quadratic function.

A=50W - W^2

Since the area of a rectangle cannot be negative (and should be positive, though it could be zero), the practical domain of A is determined when

50W - W^2\geq 0

Taking common factor W

W(50 - W)\geq 0

Since W must be positive W>0

50 - W\geq 0

Or equivalently

50 \geq W

W \leq 50

The total interval is

0 < W

Correct option: A

Please note: The real restriction should be

0 < W\leq 50

if we allowed the area to be positive, but I'm providing the most possible correct available option

6 0
3 years ago
Helppppppppppppppppppppppppp
KiRa [710]
<h2><em>Answer:</em></h2><h2><em>5</em><em>2</em><em>.</em><em>7</em><em>8</em><em>5</em><em>6</em><em> </em><em>cm</em></h2>

<em>Solution</em><em>,</em>

<em>diameter</em><em>=</em><em>1</em><em>6</em><em>.</em><em>8</em><em> </em><em>cm</em>

<em>radius=</em><em>8</em><em>.</em><em>4</em><em> </em><em>cm</em>

<em>Circumference</em><em> of</em><em> </em><em>circle</em><em>=</em><em>2</em><em> </em><em>pi </em><em>r</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>*</em><em>3</em><em>.</em><em>1</em><em>4</em><em>2</em><em>*</em><em>8</em><em>.</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>5</em><em>2</em><em>.</em><em>7</em><em>8</em><em>5</em><em>6</em><em> </em><em>cm</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

5 0
3 years ago
05 lc) if x2 = 10, what is the value of x? ±square root of 10 ±square root of 20 ±5 ±20
postnew [5]
x^2=10\\x=\pm\sqrt{10}
7 0
3 years ago
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