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never [62]
3 years ago
15

Can someone pls do these quick

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:

6. x° is approximately 21.04°

7. x° is approximately 39.56°

8. x° is approximately 58.03°

9. x° is approximately 72.85°

Step-by-step explanation:

6. In the given right triangle (a triangle with the measure of one of the interior angles equal to 90°, indicated by the small square between two sides) , we have;

The hypotenuse side length = 15

The adjacent side to the given reference angle, x° = 14

By trigonometric ratio, we have;

cos\angle X = \dfrac{Adjacent\ leg \ length}{Hypotenuse \ length}

\therefore cos(x^{\circ}) = \dfrac{14}{15}

To find the value of x°, we make use of the inverse cosine function, arccos found on a scientific calculator, as follows;

x° = arccos(14/15) ≈ 21.04°

x° ≈ 21.04°

7. In the given right triangle, we have;

The length of the opposite side to the given reference angle, x° = 19

The length of the adjacent side to the given reference angle, x° = 23

By trigonometric ratios, we have;

Tan(\angle X) = \dfrac{Opposite \, side \  length}{Adjacent\, side \ length}

\therefore tan(x^{\circ}) =  \dfrac{19}{23}

Therefore;

x° = arctan(19/23) ≈ 39.56°

x° ≈ 39.56°

8. In the given right triangle, the adjacent side to the reference angle, x° and the hypotenuse side are given, therefore, we have;

x° = arccos(9/17) ≈ 58.03°

x° ≈ 58.03°

9. The opposite side to the reference angle and the hypotenuse side are given

By trigonometric ratio, we have;

sin\angle X = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}

\therefore sin(x^{\circ}) = \dfrac{43}{45}

x° = arcsin(43/45) ≈ 72.85°

x° ≈ 72.85°.

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