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2 years ago

X^2-4x+3=0 write it in standard form.

Mathematics

2 answers:

Oliga [24]2 years ago

6 0

Step-by-step explanation:

x²-4x+3=0

x²-4x=-3

take half of -4 square it and add it to both side

x²-4x+(-2)²=4-3

(x-2)²=1

x-2=±1

x=2±1

x=1,3

trasher [3.6K]2 years ago

4 0

Answer:

√

Explanation:

there are no whole numbers which multiply to - 3

and sum to - 4

we can solve using the method of

completing the square

the coefficient of the

term is 1

∙

add subtract

(

coefficient of the x-term

) 2 to x2 − 4 x ⇒ x 2 +2(− 2 ) x + 4 − 4 − 3 = 0 ⇒ ( x − 2 )2 − 7 =0 ⇒ ( x − 2 ) 2 = 7

take the square root of both sides

⇒ x − 2 = ± √ 7 ←

note plus or minus

⇒ x = 2 ± √ 7←

exact solutions

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The triangles are similar

hoa [83]

Answer:

Part 1) $x=16\ units$

Part 2) $x=23\ units$

Part 3) $AE=20\ units$

Part 4) $x= 6.25\ units$

Part 5) $x=26.67\ in$

Step-by-step explanation:

Part 1) we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

$\frac{12}{3}=\frac{x}{4}\\\\3x=12*4\\ \\x=48/3\\ \\x=16\ units$

Part 2) we know that

If two triangles are similar

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In this problem

$\frac{36}{12}=\frac{39}{(x-10)}\\\\3(x-10)=39\\ \\x=(39/3)+10\\ \\x=23\ units$

Part 3) we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

$\frac{AB}{CD}=\frac{AE}{ED}$

substitute the values

$\frac{10}{4}=\frac{2x+10}{x+3}$

$2.5(x+3)=2x+10$

$2.5x+7.5=2x+10$

$2.5x-2x=10-7.5$

$0.5x=2.5$

$x=5\ units$

$AE=2x+10=2*5+10=20\ units$

Part 4) we know that

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In this problem

$\frac{4}{5}=\frac{5}{x}\\ \\4x=5*5\\ \\ x=25/4\\ \\ x= 6.25\ units$

Part 5) we know that

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In this problem

$\frac{30}{x}=\frac{45}{40}\\ \\45x=30*40\\ \\x=1,200/45\\ \\ x=26.67\ in$

3 0

3 years ago

Read 2 more answers

If a and B are the zeros of the quadratic polynomial f(x) = x2- 5x + 4 find the value of 1/a+1/b-2ab

bearhunter [10]

Answer:

Step-by-step explanation:

Given the quadratic polynomial given as g(x) = x²- 5x + 4, the zeros of the quadratic polynomial occurs at g(x) = 0 such that x²- 5x + 4 = 0.

Factorizing the resulting equation to get the roots

x²- 5x + 4 = 0

(x²- x)-(4 x + 4) = 0

x(x-1)-4(x-1) = 0

(x-1)(x-4) = 0

x-1 = 0 and x-4 = 0

x = 1 and x = 4

Since a and b are known to be the root then we can say a = 1 and b =4

Substituting the given values into the equation 1/a+1/b-2 ab , we will have;

= 1/1 + 1/4 - 2*1*4

= 1 + 1/4 - 8

= 5/4 - 8

Find the Lowest common multiple

= (5-32)/4

= -27/4

<em>Hence the required value is -27/4</em>

5 0

3 years ago

Please help me with this pleaseee

torisob [31]

Answer:

x = 88.2

Step-by-step explanation:

The angle at the top of the triangle = 90° - 10° = 80°

and the left side of the triangle is x ( opposite sides of a rectangle )

Using the tangent ratio in the right triangle

tan80° = $\frac{opposite}{adjacent}$ = $\frac{500}{x}$

Multiply both sides by x

x × tan80° = 500 ( divide both sides by tan80° )

x = $\frac{500}{tan80}$ ≈ 88.2

5 0

3 years ago

which equations are equivalent to 3/4+m=-7/4 check all that apply m=10/4 m=-10/4 m=-5/2 11/4+m=-1/4 -5/4+m=-15/4 m+2=-0.5 Help f

Alecsey [184]

Answer:

The correct choices are; B,C,E, and F.

Step-by-step explanation:

The given equation is;

$\frac{3}{4}+m=-\frac{7}{4}$

We solve for m to obtain:

$m=-\frac{7}{4}-\frac{3}{4}=-2.5$

We also solve the remaining equations to see which ones give the same result.

A: $m=\frac{10}{4} =2.5$

B: $m=-\frac{10}{4} =-2.5$

C: $m=-\frac{5}{2} =-2.5$

D: $\frac{11}{4}+m=-\frac{1}{4}$

$m=-\frac{1}{4}-\frac{11}{4}=-3$

E: $-\frac{5}{4}+m=-\frac{15}{4}$

$m=-\frac{15}{4}+\frac{5}{4}=-2.5$

F: $m+2=-0.5$

$m=-0.5-2=-2.5$

The equivalent equations are; B,C,E, and F.

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3 years ago

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ludmilkaskok [199]

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2 years ago