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Artist 52 [7]
3 years ago
9

Last night, the temperature fell from 0°F to -13 in 4 § hours. What was the average temperature change per hour? Solve the divis

ion problem. 2 1 -13= - 4 5 5 The temperature drop per hour can be represented by I °F. QUICKLY​
Mathematics
2 answers:
Simora [160]3 years ago
8 0

Answer:

-3.25 degrees an hour

Step-by-step explanation:

-13 ÷ 4 = -3.25

Stels [109]3 years ago
7 0

Answer:

3.25 degrees/hour

Step-by-step explanation:

Last night, the temperature fell from 0°F to -13°F in 4 hour.

We need to find the average temperature change per hour. It can be calculated by dividing the change in temperature per unit time.

Change in temperature = -13°F -0°F = -13°F

So,

C=\dfrac{-13}{4}\\\\=-3.25\ \text{degrees/hour}

So, the change in temperature is 3.25 degrees/hour.

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Solve for :<br> 12 = 15 (z - 1/5)
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Tomtit [17]

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2 years ago
HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
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