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2 years ago

Find the value of a) 4:12

Mathematics

1 answer:

Alexeev081 [22]2 years ago

4 0

Step-by-step explanation:

1:4 bcos u need to divide both sides by 4

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Find the area of the triangle. Round your answer to the nearest tenth.

marin [14]

Answer:

Fg is 6 and I have to

Step-by-step explanation:

The school timings for the next course will be a number of activities for students to participate in related to UAE culture and

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2 years ago

1-tan^2(x)/sec^2 = cos(2x)

LekaFEV [45]

By applying the formula of trigonometric function the right hand side will

be equal to right hand side which is 1- $tan^{2} x$ / $sec^{2}x$ =cos2x.

Given: 1- $tan^{2} x$ / $sec^{2}x$ =cos2x.

Taking right hand side first which is cos2x.

We know that cos2x= $1-tan^{2}x/1+tan^{2}x$

Now we will solve the left hand side of the equation give which is

1- $tan^{2} x$ / $sec^{2}x$

=1- $tan^{2}x$ /1+ $tan^{2}x$

[secant square x minus tangent square x is equal to 1]

By putting both values left hand side and right hand side we will find our solution which is :

1-tan^{2}x/1+tan^{2}x=1- $tan^{2}x$ /1+ $tan^{2}x$ .

Hence proved

Learn more about trigonometric functions at brainly.com/question/24349828

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1 year ago

Can someone tell me what 0.250 is in a fraction?

8090 [49]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

Think about it in terms of 4 quarters to equal the dollar. 0.250= 1 quarter (25). The answer is then $\frac{1}{4}$

4 0

2 years ago

Read 2 more answers

How many times can 409999 go into 20

grandymaker [24]

Your answer will be 0.0487806.

7 0

2 years ago

Read 2 more answers

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

2 years ago

Find the value of a) 4:12 ​

Find the value of a) 4:12