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pshichka [43]
3 years ago
14

Currently, the number of people entering a shopping mall is 109. It is estimated that the number of people entering the shopping

mall will decrease by 3% each hour. Find the total number of people entering the shopping mall at the end of 4 hours. (Round your answer to the nearest whole number if necessary.)
Mathematics
1 answer:
seropon [69]3 years ago
6 0

Answer:

96 people.

Step-by-step explanation:

Exponential equation for a decreasing amount:

The exponential equation for a decreasing amount is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial rate and r is the decay rate, as a decimal.

Currently, the number of people entering a shopping mall is 109.

This means that A(0) = 109

It is estimated that the number of people entering the shopping mall will decrease by 3% each hour.

This means that r = 0.03

So

A(t) = A(0)(1-r)^t

A(t) = 109(1-0.03)^t

A(t) = 109(0.97)^t

Find the total number of people entering the shopping mall at the end of 4 hours.

This is A(4). So

A(4) = 109(0.97)^4 = 96.49

Rounding to the nearest whole number, 96 people.

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A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
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3 years ago
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