Question

Given the point and slope write the equation of the line (-4, 0); slope = 1/2

Answer 1

Answer:

The equation of the line will be:

$y=\frac{1}{2}x+2$

Step-by-step explanation:

Given the point

• (-4, 0)

• slope = m = 1/2

As the equation of a line in slope-intercept form is

$y-y_1=m\left(x-x_1\right)$

• where m is the slope

substituting the values m = 1/2 and the point (-4, 0)

$y-y_1=m\left(x-x_1\right)$

$y-0=\frac{1}{2}\left(x-\left(-4\right)\right)$

$y=\frac{1}{2}\left(x-\left(-4\right)\right)$

$y=\frac{1}{2}\left(x+4\right)$

$y=\frac{1}{2}x+\frac{4}{2}$

$y=\frac{1}{2}x+2$

Therefore, the equation of the line will be:

$y=\frac{1}{2}x+2$