2 years ago

Help me ASAP please!

Mathematics

1 answer:

ella [17]2 years ago

4 0

Answer:

∠1 and ∠3

∠6 and ∠8

∠5 and ∠7

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Multiply -4x^-2y(2yx^3+6xy^3-3y^3x4)

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below here hopes it helps!

Step-by-step explanation:

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2 years ago

Last question...! And then I’m totally done with asking questions for a while. -v-;; Any answers or advice on how to solve?

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3 years ago

Write an expression that can be used to multiply 6x198 mentally

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It's believed that as many as 23% of adults over 50 never graduated from high school. We wish to see if this percentage is the

laila [671]

Answer: 756

Step-by-step explanation:

Given : The proportion of adults over 50 never graduated from high school. = 0.23

Margin of error : E=0.03

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

The formula to find the sample size is given by:_

$n=p(1-p)(\dfrac{z_{\alpha/2}\ }{E})^2$

i.e. $n=(0.23)(0.77)(\dfrac{(1.96)}{0.03})^2=755.941511111approx756$

Hence, the required minimum sample size = 756

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3 years ago

What is a common factor for the two fractional terms StartFraction 5 over 8 EndFraction x andStartFraction 11 over 8 EndFraction

Dafna1 [17]

Answer:

$\frac{1}{8x}$

Step-by-step explanation:

Given two fractional terms $\frac{5}{8x}\ and\ \frac{11}{8xy}$ . Their common factor is a value or function that can go in both fractional terms. The terms can be written as shown.

$\frac{5}{8x} = 5 *\frac{1}{8x}$

$\frac{11}{8xy} = 11 * \frac{1}{8x} * \frac{1}{y}$

It can be seen from the both equations that they both have $\frac{1}{8x}$ as one of their factors i.e <em>1/8x is common to both fractional terms</em>. This gives the common factor for the two fractional terms as $\frac{1}{8x}$

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2 years ago

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