Answer:
Step-by-step explanation:
assuming that weekends are only sat and sunday
24 students
or
if were assuming that friday is included
30 students
hope this helps <3
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
Part 1) Find the lateral area of the pyramid
we know that
The lateral area of the pyramid, is equal to the area of six congruent isosceles triangles
so
![LA=6[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
Applying Pythagorean Theorem calculate the height of triangle
simplify
Find the lateral area
![LA=6[\frac{1}{2}(6)(6\sqrt{2})]\\\\LA=108\sqrt{2}\ in^2](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%286%29%286%5Csqrt%7B2%7D%29%5D%5C%5C%5C%5CLA%3D108%5Csqrt%7B2%7D%5C%20in%5E2)
Part 2) Find the base area
we know that
The area of a regular hexagon is equal to the area of six equilateral triangles
so
Applying the law of sines to calculate the area of triangle
![B=6[\frac{1}{2}b^2sin(60^o)]](https://tex.z-dn.net/?f=B%3D6%5B%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29%5D)
we have
substitute
![B=6[\frac{1}{2}6^2(\frac{\sqrt{3}}{2})]](https://tex.z-dn.net/?f=B%3D6%5B%5Cfrac%7B1%7D%7B2%7D6%5E2%28%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%29%5D)
Answer: B
Step-by-step explanation:
You take 907 and place it above the 728
907
-728
Always start with the ones side. (Right)
You cannot subtract 8 from 7, so you'll need to borrow from a number. Can you borrow from 0? No, because 0 equals to nothing. Can you borrow from 9?
Yes.
So, imagine taking 1 out of 9, and that leaves you with 8 because, well, 9 - 1 = 8.
Now the 0 has a 1, which makes it 10
Which means 10 is greater than 7, so you can borrow a 1 from there.
10 - 1 = 9 So you are left with 9 in the tens column.
10 + 7 = 17, which is greater than 8 so you can subtract that now.
17 - 8 = 9 (Ones column)
10 - 2 = 8 (Tens column)
8 - 7 = 1 (Hundreds column)
So, your answer is 189. Try it on a paper, or simply use a calculator.
Hope this helps! c:
