H(t) = -16t² + vt + s
Where -16 is half of the gravitational constant of almost 32 ft/sec (downward, thus negative),
v is the initial velocity (90), and
s is the starting height (160)
so we have:
H(t) = -16t² + 90t + 160
How long before it hits the ground? Solve for h(t) = 0:
0 = -16t² + 90t + 160
Divide both sides by -2:
0 = 8t² - 45t - 80
Quadratic equation:
t = [ -b ± √(b² - 4ac)] / (2a)
t = [ -(-45) ± √((-45)² - 4(8)(-80))] / (2(8))
t = [ 45 ± √(2025 + 2560)] / 16
t = [ 45 ± √(4585)] / 16
throwing out the negative time:
t = (45 + √4585) / 16
t ≈ 7.04 seconds
Can you please provide a photo so I can help you?
Step-by-step explanation:
Slope (m) = 2/ 5
Y-intercept (c) = - 7
writing in slope intercept form
y = mx + c
y = 2/5 x - 7
Hope it will help :)
You will read for 45 minutes if your brother reads for 15 minutes.
<em><u>Explanation</u></em>
You decide to read 30 minutes longer than your brother reads.
If your brother reads 
number of minutes, then 30 minutes longer than minutes means 
minutes.
As the number of minutes you read is 
, so the equation will be: 
When your brother reads for 15 minutes, then we will just <u>plug 
into the above equation</u>. So.....
So, you will read for 45 minutes if your brother reads for 15 minutes.
Answer:
The correct answer is B) 1555.6
Step-by-step explanation:
In order to find this, we must divide the part by the percentage. This will give us the total out of 100%
140/.09 = 1555.6
