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nevsk [136]
2 years ago
11

Suppose your family buys a "movie card" from a DVD

Mathematics
1 answer:
topjm [15]2 years ago
8 0
Y = 3x + 25, because I’m assuming that that you start by renting 25 movies.
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At a football stadium, 20% of the fans in attendance were teenagers. If there were 180
wolverine [178]
The answer is 900 people.
4 0
2 years ago
PLEASEE Can someone help me with this and show the work
Orlov [11]

Answer:

The vertex form is: y =  3(x-2)^2 + 7 . The vertex is (2, 7)

Step-by-step explanation:

Write the function: y = 3x^2 - 12x + 11 in vertex form

The vertex form of a quadratic equation is:

y = m(x - a)^2 + b where (a,b) is the vertex

For y = 3x^2 - 12x + 11

Solve for m

y = 3(x^2 - 4x) + 11

Complete the Square:

y = 3(x^2 - 4x + 4) + 11 - 4

y = 3(x - 2)^2 + 7

The vertex then is (2, 7)

3 0
3 years ago
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Nicole is driving on a highway. She uses one gallon of gas every 20 miles she drives. The distance, D (in miles), she travels on
Arada [10]

Answer:

60

Step-by-step explanation:

1 gallon is equal to 30 miles, which would mean if she uses 30 gallons of gas it would be equal to 60 since 3 x 20 equals 60

8 0
2 years ago
Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r
PolarNik [594]

Answer:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

(a-b)^2=a^2-2ab+b^2

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}

\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8

\displaystyle b=\frac{1}{7}mpz^4

Nos cercioramos de que el término central es 2ab:

\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4

Operando:

\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5

Una vez verificado, ahora podemos decir que:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

5 0
2 years ago
How many unique triangles can be formed with two side lengths of 10 centimeters and one 40° angle?
r-ruslan [8.4K]

Answer:

  • Two unique triangles possible

Step-by-step explanation:

Given two sides of 10 cm and one 40° angle

<u>If we use these, we'll get isosceles triangle with:</u>

1. Included 40° angle.

<u>Then the other angles will be same and measure:</u>

  • (180° - 40°)/2 = 70°

2. Adjacent 40° angle. Then one of the angles must be 40° angle as opposite of 10 cm sides.

<u>The remaining angle will measure:</u>

  • 180° - 2*40° = 100°

There no more unique triangles possible, so the answer is two.

3 0
2 years ago
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