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3 years ago

Solve.

Mathematics

2 answers:

Nataly_w [17]3 years ago

6 0

Answer:

3 , 9/2

Step-by-step explanation:

(3- y) (2 y– 9)=0

y=3 , y= 9/2

Tems11 [23]3 years ago

4 0

Hope this helps! feel free to clarify

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Choose the equation for the graph.

Marina CMI [18]

Answer:

Step-by-step explanation:

You just find the rate of change. So you would divide 30/1 which equals 30. So the equation is y=30x.

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3 years ago

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Lisa [10]

Answer:

Decay

Step-by-step explanation:

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3 years ago

Classify the triangle with side lengths 11 cm, 30 cm, and 39 cm as acute, right, or obtuse

Ahat [919]

Answer:

This triangle is a obtuse traingle.

Step-by-step explanation:

First of all, it is impossible that this triangle is actute since the sides are different length.

Right is also not possible ( in this case ) because there are two pretty far sides.

30, 39

A obtuse triangle have a short side of 11 cm pointing top right and a side of 30 cm pointing directly to the right and the 39 cm side connecting the ends of the other sides.

\ Third side ( 39 cm , the one connecting

First side ( 11 cm ) \ the ends of side 1 and 2)

\______________

Second side ( 30 cm )

<h3><u><em>Please rate this and please give brainliest. Thanks!!! </em></u></h3><h3><u><em>Appreciate it! : )</em></u></h3><h3><u><em></em></u></h3><h2><u><em>And always, </em></u></h2><h2><u><em> SIMPLIFY BANANAS : )</em></u></h2>

5 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

2sin^2 2x=2<br><br> In the domain [0, 2pi)

djverab [1.8K]

Please type this as 2(sin 2x)^2=2 <span>2sin^2 2x=2 is confusing.

Reducing this expression: (sin 2x)^2 = 1

Taking the sqrt of both sides, sin 2x = plus or minus 1

If sin 2x = 1, then 2x must be pi/2 or 3pi/2, and so x must be pi/4 or 3pi/4.

Now you do this for sin 2x = -1.</span>

8 0

3 years ago