(x^2+5x-36)/(x^2-16)
=(x^2+9x-4x-36)/(x^2-4^2)
=x(x+9)-4(x+9)/(x+4)(x-4)
=(x-4)(x+9)/(x+4)(x-4)
=x+9/x+4
Hope this helps.
Answer:
c(x)=(x+3)^2+5
Step-by-step explanation:
To complete the square, the same value needs to be added to both sides.
So, to complete the square x^2+6x+9=(x+3)^2 add 9 to the expression
C(x) =x^2 +6x + 9 + 14
Since 9 was added to the right-hand side also add 9 to the left-hand side
C(x) +9= x^2 +6x + 9 + 14
Using a^2 + 2ab + b^2=(a+b)^2, factor the expression
C(x)+9= (x+3)^2 +14
Move constant to the right-hand side and change its sign
C(x)=(x+3)^2 +14 - 9
Subtract the numbers
C(x)= (x+3)^2 +5
I have attached an image of the process I used
<h2>
The required "option B) 
" is correct.</h2>
Step-by-step explanation:
You can refer figure:
brainly.com/question/4386376
To find, the value of x = ?
We know that,
Consecutive angles are supplementary
The diagonals bisect the angles.
Divided by 2 both sides, we get
⇒ 
⇒ 
⇒ 
⇒ 4x = 
⇒ 
⇒ 
∴ The value of x =
Thus, the required "option B) " is correct.
