Answer:
Third option
![y-3=4(x-1)](https://tex.z-dn.net/?f=y-3%3D4%28x-1%29)
Step-by-step explanation:
Equation of straight line in point slope form is given as
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
Here
slope=m=4 and ![(x_1, y_1) = ( 1, 3 )](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29%20%3D%20%28%201%2C%203%20%29)
Equation of straight line having slope 4 and crossing from point (1, 3) is given as
![y-3=4(x-1)](https://tex.z-dn.net/?f=y-3%3D4%28x-1%29)
Answer:
y = 3x + 12
Step-by-step explanation:
Slope of y = 3x + 5 is 3
Line parallel will have same slope 3
Line intersects point at (-2, 6)
Replace into y = mx + b to find
6 = 3(-2) + b
6 = -6 + b
12 = b
Equation of line:
y = 3x + 12
#b
See AB||CD
Hence
![\\ \rm\Rrightarrow](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%3CBGH%3D%3CGHD)
![\\ \rm\Rrightarrow 90=90](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%2090%3D90)
![\\ \rm\Rrightarrow \dfrac{1}{2}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%5Cdfrac%7B1%7D%7B2%7D%3CBGH%3D%5Cdfrac%7B1%7D%7B2%7D%3CGHD)
![\\ \rm\Rrightarrow](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20%3CHGP%3D%3CGHP%3D45%C2%B0)
Now using angle sum property
![\\ \rm\Rrightarrow a+45+45=180](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20a%2B45%2B45%3D180)
![\\ \rm\Rrightarrow a=180-90](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20a%3D180-90)
![\\ \rm\Rrightarrow a=90](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRrightarrow%20a%3D90)
Answer:
B
Step-by-step explanation:
X^5 = 1024 = 4^5
Therefore, x = 4.
Given, (-1/7)^-x = -1/343
(1/7)^-x = 1/343
(1/7)^-x = (1/7)^3
-x = 3
x = -3