Answer:
= 99 Ω
= 2.3094 Ω
P(98<R<102) = 0.5696
Step-by-step explanation:
The mean resistance is the average of edge values of interval.
Hence,
The mean resistance,
= 99 Ω
To find the standard deviation of resistance, we need to find variance first.

Hence,
The standard deviation of resistance,
= 2.3094 Ω
To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.


From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696
Answer:
The answer is 6+3b<or equal to 15
Step-by-step explanation:
Answer:
A. Men had less distress from nausea on average than women but we can not determine if this is a significant difference.
Step-by-step explanation:
Working based on the information given, the mean values of each group with with men having an average score of 1.02 and women have an average of 1.79 this reveals that distressing nausea on average is higher in women than in men . However, to test if there is a significant difference would be challenging as the information given isn't enough to make proceed with the test as the standard deviations of the two groups aren't given and no accompanying sample data is given.
Answer:
-14
Step-by-step explanation:
f(x) = 3x-5
g(x) = -x^2 +1
g(2) = - (2^2) +1
g(2) =-4+1 = -3
Then stick the -3 in f(x)
f(-3) = 3(-3)-5 = -9 -5 = -14
f(g(2) = -14
Answer: 66
Step-by-step explanation:
To solve for x in x+27=93, subtract both sides of the equation by 27
X + 27 -27= 93 - 27
X= 66
I hope this helps