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3 years ago

Find the distance between points P(8,8) and Q(4,9) to the nearest tenth

Mathematics

1 answer:

vova2212 [387]3 years ago

4 0

Use the distance formula

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Need help with graphing

astraxan [27]

Plot these points
vertex: (-4,-7)
x intercepts: (-5.5,0), (-2.5, 0)
and those two other points
the graph should look something like this:

3 0

3 years ago

Write an inequality for each sentence.<br> More than 3400 people attended the tea market.

vladimir1956 [14]

The answer would be

~X > 3400~

Hope this helps

Have a great day/night

Feel free to ask any questions

8 0

2 years ago

Read 2 more answers

Hi ! How to solve this question?

tester [92]

You should actually have

$-x^2-4x-10=-(x^2+4x+10)=-(x^2+4x+4+6)=-((x+2)^2+6)=-(x+2)^2-6$

Now, remember that $x^2$ is always non-negative, so $(x+2)^2\ge0$ for any value of $x$ . This means $-(x+2)^2\le0$ for any $x$ , and so

$-(x+2)^2-6\le0-6=-6$

i.e. f(x) is at most -6, and hence negative for all $x$ .

4 0

3 years ago

Find the integral <br> ∫√(9+x)/(9-x)

densk [106]

I suppose you mean

$\displaystyle \int \frac{\sqrt{9+x}}{9-x} \, dx$

Substitute y = √(9 + x). Solving for x gives x = y² - 9, so that 9 - x = 18 - y², and we have differential dx = 2y dy. Replacing everything in the integral gives

$\displaystyle \int \frac{2y^2}{18 - y^2} \, dy$

Simplify the integrand by dividing:

$\dfrac{2y^2}{18 - y^2} = -2 + \dfrac{36}{18 - y^2}$

$\implies \displaystyle \int \left(\frac{36}{18-y^2} - 2\right) \, dy$

For the first term of this new integral, we have the partial fraction expansion

$\dfrac1{18 - y^2} = \dfrac1{\sqrt{72}} \left(\dfrac1{\sqrt{18}-y} + \dfrac1{\sqrt{18}+y}\right)$

$\implies \displaystyle \frac{36}{\sqrt{72}} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

The rest is trivial:

$\displaystyle \sqrt{18} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

$= \displaystyle \sqrt{18} \left(\ln\left|\sqrt{18}+y\right| - \ln\left|\sqrt{18}-y\right|\right) - 2y + C$

$= \displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+y}{\sqrt{18}-y}\right| - 2y + C$

$= \boxed{\displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+\sqrt{9+x}}{\sqrt{18}-\sqrt{9+x}}\right| - 2\sqrt{9+x} + C}$

6 0

2 years ago

What is the sum of9x+7

aleksley [76]

Impossible question. Need at least the answer, unless it equals 0

5 0

3 years ago