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kupik [55]
3 years ago
11

C

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

2x² - 6x

Step-by-step explanation:

(3x² - 4x + 8) + (- x² - 2x - 8) ← remove both parenthesis

= 3x² - 4x + 8 - x² - 2x - 8 ← collect like terms

= 2x² - 6x

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Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}

\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
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Flauer [41]
4,398,200 is your answer

hope this helps
7 0
3 years ago
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Aleks [24]
2/4= 10/20
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3 years ago
What is the value of the expression below when y=7?<br><br><br> y2+5y+6
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Answer:

90

Step-by-step explanation:

y^2 + 5y + 6 =

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49 + 35 + 6 =

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90

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