Answer:
a) (11/7, 9/7)
b) There's no point of intersection
Step-by-step explanation:
a) x - 2y + 1 = 0
2x + 3y - 7 = 0
To find the point of intersection, we need to solve the system of equations and the result will be the point of intersection (x,y)
Now we substitute x in the second equation:
Now we substitute y in our first equation.
.
The point of intersection is (11/7, 9/7)
b) x -2y +11 =0
-x + 2y - 13 =0
We are going to follow the same procedure:
Since this system of equations doesn't have a solution, the system has no point of intersection.
the answer is c you just have to solve each one
Z = 25. y = 101. I got this because of the parallel lines theorem. In essence, what this theorem means is that the alternate exterior angles are congruent. If you see, this means that 6z - 71 = 79. After solving this equation, you get z = 25. y = 101 because of supplementary angles. Z is 25, but the value of that angle is not 25 because first, you have to solve the equation, in which you get 79. 180 - 79 = 101.
Z = 25.
Y = 101.
You have to distribute 3x+1 over the other parentheses
3x(2x^2 +4x-3) + 1• ( 2x^2 +4x-3)=
6x^3 +12x^2 -9x + 2x^2 +4x-3 =
Combine like terms
6x^3 +14x^2 -5x -3
Answer
given,
a) x-1=0
adding both side with 1
x = 1
b) x + 1 =0
subtracting both side by 1
x = -1
c) x²- 1 =0
x² = 1
taking square root
x = √1
x = 1
d) x²+ 1 =0
x² = -1
taking square root
x = √-1
x = i (iota)
