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zzz [600]
3 years ago
6

Which pair of points are 4 units apart?

Mathematics
1 answer:
Basile [38]3 years ago
7 0

Answer:

B

Step-by-step explanation:

-1+4=3

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Very urgent....plz help!
Len [333]

Answer:

  none of the above. (Talk to your teacher about this question.)

Step-by-step explanation:

The differences between length and width are 4, 6, 12, so are not constant at either 4 or 6.

The ratio of width to length is 2/3, 2/3, 3/5, so is not constant at 2/3 or 3/2.

None of the answer choices (even after editing to add appropriate math symbols) describes the relation between length and width.

4 0
3 years ago
How many different simple random samples of size 5 cab be obtained from a population whose size is 46
otez555 [7]

Answer:

1370754

Step-by-step explanation:

From what I can see, you are probably studying combinations and permutations at the moment. Since this is a question about how many groups of five can be produced from a sample size of 46, the groups are random and not in order, which may rule for us to use the combination formula.

Once you compute this, this answer is basically saying that 1370754 groups of 5 can be created from a sample size of 46

8 0
4 years ago
Write an equivalent expression by distributing the " sign outside the parentheses: 5n - (7.4p - 9.6​
liberstina [14]
5n - 7.4p + 9.6 is the answe
4 0
3 years ago
2. The functions ???? and ???? represent the population of two different kinds of bacteria, where x is the time (in hours) and ?
klio [65]

Answer:

(a) Bacterial 1 had a faster rate of growth.

(b) The population of f(x) always exceed the population of g(x). In other words, population of g(x) cannot exceed the population of f(x).

Step-by-step explanation:

Consider the given functions are

f(x)=2x^2+7

g(x)=2x

where, x is the time (in hours) and f(x) and g(x) are the number of bacteria (in thousands).

(a)

The rate of change of a function f(x) on [a,b] is

m=\frac{f(b)-f(a)}{b-a}

Rate of change between third and sixth hour of first function is

m_1=\frac{f(6)-f(3)}{6-3}

m_1=\frac{(2(6)^2+7)-(2(3)^2+7)}{6-3}

m_1=\frac{79-25}{3}

m_1=\frac{54}{3}

m_1=18

Rate of change between third and sixth hour of second function is

m_2=\frac{g(6)-g(3)}{6-3}

m_2=\frac{2(6)-2(3)}{6-3}

m_2=\frac{12-6}{3}

m_2=\frac{6}{3}

m_2=2

Since m_1>m_2, therefore bacterial 1 had a faster rate of growth.

(b)

The initial population of f(x) is 7 and it increases exponentially.

The initial population of g(x) is 0 and it increases linearly.

It means population of f(x) always exceed the population of g(x).

In other words, population of g(x) cannot exceed the population of f(x).

8 0
3 years ago
Solve for x<br> (x+54)<br> 5x
valina [46]
X=9

You would do 54 divided by 5x and it would equal to 9 that means x is 9
4 0
3 years ago
Read 2 more answers
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