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lawyer [7]
3 years ago
9

Jackson flipped a coin ten times. He flipped heads 4 times and tails 6 times. What is the experimental probability that Jackson

will flip heads on his next flip?
Mathematics
1 answer:
ololo11 [35]3 years ago
4 0
1/2 because there are 2 options , heads or tails
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What is three billion,two million,forty-two thousand, seven hundred sixty-five in expanded form
Shtirlitz [24]
3,000,000,000+2,000,000+40,000+2,000+70*+60+5
7 0
3 years ago
Simplify these expressions.<br> a. 4x + 7x + (–x)<br> b. –5yz + yz + 2yz
salantis [7]

Answer:A. 10x. B. -2yz

Step-by-step explanation:

A. 4x+7x=11x

11x+(-x) = 11x-1x=10x

B. -5yz+yz=-4yz

-4yz+2yz=-2yz

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Find the area of the circle. Round your answer to two decimal places, if necessary.
Dmitry_Shevchenko [17]

Step-by-step explanation:

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5 0
2 years ago
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State two numbers such that the lesser number is 25% less than the greater number.
Lorico [155]
75 and 100.

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8 0
3 years ago
Read 2 more answers
Inequality to x2 &lt; 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
3 years ago
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