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DaniilM [7]
3 years ago
13

Label each answergiving brainly for all three correct answers

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
6 0

Answer: B, C, B

Hope this helps!

dexar [7]3 years ago
4 0
B, C and B :^>


I hope I’m correct :)
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If (3x2 + 22x + 7) ÷(x + 7) = 3x + 1, then (x + 7)( ) = . The check of the polynomial division problem shows that the product of
azamat

Answer:

(x + 7) * (3x + 1) = (3x^2 + 22x + 7)

Step-by-step explanation:

Given

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

(x + 7) * (\ ) = [\ ]

Required

Complete the blanks

We have:

(3x^2 + 22x + 7) \div (x + 7) = 3x + 1

Rewrite as:

\frac{(3x^2 + 22x + 7) }{ (x + 7)} = 3x + 1

Cross multiply

(x + 7) * (3x + 1) = (3x^2 + 22x + 7)

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3 years ago
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A mass of 1 g is set in motion from its equilibrium position with an initial velocity of 6in/sec, with no damping and a spring c
yan [13]

a) y(t)=0.0016 sin(94.9t) [m]

b) 0.033 s

c) -0.152 m/s

Step-by-step explanation:

a)

The force acting on the mass-spring system is (restoring force)

F=-ky

where

k = 9 is the spring constant

y is the displacement

Also, from Newton's second law of motion, we know that

F=my''

where

m = 1 g = 0.001 kg is the mass

y'' is the acceleration

Combining the two equations,

my''=-ky

This is a second order differential equation; the solution for y(t) is

y(t)=A sin(\omega t-\phi)

where

A is the amplitude of motion

\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{0.001}}=94.9 rad/s is the angular frequency

The spring starts its motion from its equilibrium position, this means that y=0 when t=0; therefore, the phase shift must be

\phi=0

So the displacement is

y(t)=A sin(\omega t)

The velocity of the spring is equal to the derivative of the displacement:

v(t)=y'(t)=\omega A cos(\omega t)

We know that at t = 0, the initial velocity is 6 in/s; since 1 in = 2.54 cm = 0.0254 m,

v_0=6(0.0254)=0.152 m/s

And since at t = 0, cos(\omega t)=1

Then we have:

v_0=\omega A

From which we find the amplitude:

A=\frac{v_0}{\omega}=\frac{0.152}{94.9}=0.0016 m

So the solution for the displacement is

y(t)=0.0016 sin(94.9t) [m]

b)

Here we want to find the time t at which the mass returns to equilibrium, so the time t at which

y=0

This means that

sin(\omega t)=0

We know already that the first time at which this occurs is

t = 0

Which is the beginning of the motion.

The next occurence of y = 0 is instead when

\omega t = \pi

which means:

t=\frac{\pi}{\omega}=\frac{\pi}{94.9}=0.033 s

c)

As said in part a), the velocity of the mass-spring system at time t is given by the derivative of the displacement, so

v(t)=\omega A cos(\omega t)

where we have

\omega=94.9 rad/s is the angular frequency

A=0.0016 m is the amplitude of motion

t is the time

Here we want to find the velocity of the mass when the time is that calculated in part b):

t = 0.033 s

Substituting into the equation, we find:

v(0.033)=(94.9)(0.0016)cos(94.9\cdot 0.033)=-0.152 m/s

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Answer:

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1.  384 feet squared 2. 60 cubic feet 60 3. 444

Step-by-step explanation:

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License plates in a particular state display 4 letters followed by 2 numbers. How many different license plates can be manufactu
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