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antoniya [11.8K]
3 years ago
10

Greg enjoys jogging 4 times a week. On the first day he jogs 3 1/2 miles. on the second day he jogs 3 2/3 miles. on the third da

y he jogged 2 1/4 miles. on the fourth day he jogged 4 miles. What is the total distance Greg jogs?
Mathematics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

The exact form is 161/12 but the mixed number is 13 5/12

Step-by-step explanation:

You need to find a common donominator for all of the fractions 2,3,4 all go into 12 so I multiplied 1/2x6 (multiply both 1 and 2 by 6 same with all the others) then 2/3x4 and 1/4x3. That should get you 6/12 8/12 and 3/12. Add all of those and then add all of the whole numbers.

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My values:
lesya692 [45]
You should go by 0.001
so you can graph 0.001, 0.002, 0.003, and so on
7 0
3 years ago
How would you write the name of a ray differently than the name of a line? What symbols would you use?
matrenka [14]

For a line you would draw a straight line with arrows on each end and for a ray you would draw a straight line with an arrow on only one end (depends on which way ray is pointing)

:)

3 0
4 years ago
I don't know how do this, I know that I use L'hopitals Rule, I just don't know who to start.
Novosadov [1.4K]
Lim[x.sin(4π/x)] when x →∞. To apply the Hospital rule we need a fraction:

lim[x.sin(4π/x)] could be written:

lim [sin(4π/x)] / (1/x) . Now let's find the derivative of the numerator and the denominator:

Numerator = sin(4π/x) → (Numerator)' = cos(4π/x).(-4π/x²) [Chaine rule
(sinu)' = cosu. u'] So derivative of Numerator = cos(4π/x).(-4π/x²)

Denominator = 1/x → Numerator derivative = -1/x²

Now : (numerator)'/(denominator)' = cos(4π/x).(-4π/x²) / -1/x²
Simplify by x² : → cos(4π/x).(-4π) / -1

OR  cos(4π/x).(4π) . When x→∞ , 4π/x → 0 and cos(0) = 1, then:

lim[x.sin(4π/x)] when x →∞. is 4π

5 0
3 years ago
Deshaun works as a tutor for 15 an hour and as a waiter for an hour. This month, he worked a combined total of hours at his two
Valentin [98]

Answer:

Total Earning = 15b + M(N - b)

where:

b is the total hours worked as a tutor

M is the amount earned by Deshaun per hour as a waiter

N is the total number of possible hours Deshaun can work in a month

Step-by-step explanation:

Let the number of hours Deshaun works daily as a waiter be w

and the time worked daily as a tutor be t

Deshaun earns $15 per hour as tutor hence daily earnings on tutoring = 15t

Let Deshaun earn $M per hour as waiter, hence daily earning as a waiter is Mw

The total possible hours Deshaun can work in a month is dependent on conditions not specified.

However, assuming 24 working days (6 days weekly for 4 weeks) in a month with maximum approved work hours of 12 hours daily

total hours Deshaun can work will equal 24 x 12 = 288hrs

Note: This 288hrs is an estimate and can change based on applicable hours of work daily and number of working days in a month; it can also be represented as N

If b is the total hours Deshaun worked as a tutor this month,

the hours Deshaun can work as a waiter in a month is equal to 288 - b

Hence in a month, Deshaun will earn 15b as a tutor and M(288-b) as a waiter or optionally M(N - b)

Therefore combined dollar amount earned in a month is

Total Earning = 15b + M(N - b)

7 0
3 years ago
Let an denote the nth term of a geometric sequence. let a0=256 and an+1=0.5an .
dusya [7]

The explicit formula is a_{n-1} = 256 * 0.5^{n-1 and the sum of the first 25 terms is approximately 512

<h3>The explicit formula</h3>

The given parameters are:

a_0 = 256

a_{n +1} = 0.5a_n

Set n = 0

a_1 = 0.5a_0

Substitute 256 for a0

a_1 = 0.5 * 256

a_1 = 128

This means that the common ratio is 0.5.

The explicit formula is then represented as:

a_{n-1} = a_0 * r^{n-1

This gives

a_{n-1} = 256 * 0.5^{n-1

<h3>The sum of the first 25 terms</h3>

This is calculated using:

S_n = \frac{a_0(r^{n-1} -1)}{r - 1}

This gives

S_{25} = \frac{256 * (0.5^{25-1} -1)}{0.5 - 1}

Evaluate

S_{25} = 512

Hence, the sum of the first 25 terms is approximately 512

Read more about geometric series at:

brainly.com/question/24643676

#SPJ1

3 0
2 years ago
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