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nexus9112 [7]
3 years ago
12

Calculate the probability of drawing an ace of spades, followed by an ace of hearts from a full deck ​

Mathematics
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

Plzzzz answer fast......

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(I need these answered asap and with work and explanation included)
erik [133]

Answer:

blue marbles - 2/9. red marbles - 3/9 = 1/3 clear marbles - 4/9. Davis got a 2/9 chance and Tessa got a 2/8 or 1/4 chance. I don't know about the last question. it might be 5/9 but I don't know sorry.

4 0
2 years ago
This is really confusing me:<br> Simplify so that your answers contain only positive exponents.
xxTIMURxx [149]

Answer:

  see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

  a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}

__

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9

3 0
3 years ago
Nia has numbers cards for 2,3,8,9,and 5.What are all the different ways Nia can arrange the cards to show only even numbers with
Natalija [7]

Answer:

any order where 2 is the last number in the sequence

Step-by-step explanation:

the ten-thousand place in 12,345 is 5.

ex: 3,8,9,5,2

5,9,8,3,2

8,9,5,3,2

5 0
3 years ago
There are five different cards numbered 1 through 5. Assume the cards are randomly chosen. If the first card picked was a 2 and
alexandr402 [8]

Answer:

Step-by-step explanation:

3 0
3 years ago
3x^2-5=43 how do i solve this using the square root property
slava [35]

Answer:

x = 4

x = -4

Step-by-step explanation:

bro i dont know but i hope this help a little, sorry

4 0
3 years ago
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