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Andre45 [30]
3 years ago
12

5                 3                4               7          26       30

Mathematics
2 answers:
erik [133]3 years ago
8 0
Ok so it goes up by 2 then by 1 then 3 then 4 then down 21
Furkat [3]3 years ago
4 0
Please explain more to the question where do the numbers go
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Solve mixture problems. George wishes to increase the percent of acid in 50m / of a 15% acid solution in water to 25% acid, how
fenix001 [56]

Answer:

x = amount of pure acid to be added = 6.67ml

Step-by-step explanation:

George wishes to increase the percent of acid in 50ml of a 15% acid solution in water to 25% acid, how much pure acid must you add?

let

x = amount of pure acid to be added

15% of 50 + x = 25% of 50 + x

(0.15 * 50) + x = 0.25(50 + x)

7.5 + x = 12.5 + 0.25x

Collect like terms

x - 0.25x = 12.5 - 7.5

0.75x = 5

x = 5/0.75

x = 6.6666666666666

Approximately,

x = 6.67

x = amount of pure acid to be added = 6.67ml

7 0
3 years ago
1/2r+2(3/4r-1)=1/4r+6
bixtya [17]
I think r should equal 32/7
3 0
3 years ago
Determine the coordinates for the intersection of the diagonals in RSTU with vertices at R(-8,-2),S(-6,7), T(6,7) and U(4,-2)
irina [24]
It is answer choice A. (-1, 2.5)
6 0
3 years ago
Read 2 more answers
I need help with my math
Tresset [83]
What is the question 
3 0
3 years ago
The options are<br> 40<br> 80<br> 120<br> 140
Nataly [62]
<h2>Here we go ~ </h2>

According to given figure,

\qquad \sf  \dashrightarrow \: \angle ABC + 60° = 180°

\qquad \sf  \dashrightarrow \: \angle ABC = 180 \degree - 60 \degree

[ By linear pair ]

\qquad \sf  \dashrightarrow \: \angle ABC = 120 \degree

now, we can see that :

\qquad \sf  \dashrightarrow \: \angle ABC + \angle BAC = \angle 1

[ By Exterior angle property of Triangle ]

\qquad \sf  \dashrightarrow \: \angle 1  = 20 \degree + 120 \degree

\qquad \sf  \dashrightarrow \: \angle 1  = 140 \degree

4 0
2 years ago
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