Firstly, subtract 3 on both sides of the equation: ![d-3=at^2](https://tex.z-dn.net/?f=%20d-3%3Dat%5E2%20)
Next, divide by a: ![\frac{d-3}{a}=t^2](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd-3%7D%7Ba%7D%3Dt%5E2%20)
Lastly, square root both sides, and your answer will be ![\pm \sqrt{\frac{d-3}{a}}=t](https://tex.z-dn.net/?f=%20%5Cpm%20%5Csqrt%7B%5Cfrac%7Bd-3%7D%7Ba%7D%7D%3Dt%20)
Answer:
Step-by-step explanation:
A school has two computer labs and each lan has 30 computers. This means that the total number of computers is the sum of the number of computers in each lab
Total number of computers = 30+30 = 60
A total of six computers in the school or not working.
The expression that can be used to find the number of working computers in the school will be
Let the number of computers that are working be x
the number of computers that are working is total number of computers minus the number of computers that are not working be
The expression that can be used to find the number of working computers in the school will be
x = 60 - 6
x = 54
Answer:
The multiplier is 1
specifically:
![\frac{6}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B6%7D%20)
Step-by-step explanation:
Let the multiplier be k
Then,
![\frac{5}{7} \times k = \frac{30}{42}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B7%7D%20%20%5Ctimes%20k%20%3D%20%20%5Cfrac%7B30%7D%7B42%7D%20)
We multiply both sides by 7/5
![\frac{7}{5} \times \frac{5}{7} k = \frac{30}{42} \times \frac{7}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B5%7D%20%20%5Ctimes%20%20%5Cfrac%7B5%7D%7B7%7D%20k%20%3D%20%20%5Cfrac%7B30%7D%7B42%7D%20%20%5Ctimes%20%20%5Cfrac%7B7%7D%7B5%7D%20)
![k = \frac{6}{6}](https://tex.z-dn.net/?f=k%20%3D%20%20%5Cfrac%7B6%7D%7B6%7D%20)
We can simplify this further to get 1.
This implies that:
![\frac{5}{7} \times \frac{6}{6} = \frac{30}{42}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B7%7D%20%20%5Ctimes%20%20%5Cfrac%7B6%7D%7B6%7D%20%3D%20%20%5Cfrac%7B30%7D%7B42%7D%20)
Hence the multiplier is 1.
Answer:
The answer is ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Step-by-step explanation:
When we divide two fractions, we multiply the numerator by the inverse of the denominator. So
![\frac{\frac{a}{5}}{\frac{3a}{10}} = \frac{a}{5} \times \frac{10}{3a} = \frac{10*a}{5*3a} = \frac{10a}{15a} = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7Ba%7D%7B5%7D%7D%7B%5Cfrac%7B3a%7D%7B10%7D%7D%20%3D%20%5Cfrac%7Ba%7D%7B5%7D%20%5Ctimes%20%5Cfrac%7B10%7D%7B3a%7D%20%3D%20%5Cfrac%7B10%2Aa%7D%7B5%2A3a%7D%20%3D%20%5Cfrac%7B10a%7D%7B15a%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
The answer is ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
I'all say the 2 line because if all those zeros are there then it will add to a zero. and Happy Valentine dat