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4 years ago

Please help me im no good w math

Mathematics

1 answer:

Katarina [22]4 years ago

7 0

Answer:

No, the answer is incorrect.

Step-by-step explanation:

First, multiply 4.6 and 2, you will get 9.6.

Next, you will subtract the exponents.

8 minus 3 is 5 so it is incorrect. The correct answer is 9.6 × 10^5 not 9.6 × 10^-5.

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What Is 5 1/2 - 2 5/6? Explain Your Answer

natulia [17]

Answer:

2 2/3

Step-by-step explanation:

Make them into improper fractions first.

11/2 - 17-6

Then multiply 11/2 so that they have common denominators.

33/6 - 17/6

Then solve.

33/6 - 17/6 = 16/6

Then convert back into a mixed number.

2 4/6 or 2 2/3

5 0

3 years ago

Which of the following sets represents the domain of the function shown?

Kobotan [32]

"2, 4 5, 11" is the one set among the following choices given in the question that represents <span>the domain of the function shown. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your desired help.</span>

8 0

4 years ago

A coin is thrown 3 times. What is the probability that at least one head is thrown?.

zvonat [6]

Answer:7/8

A coin is tossed 3 times. The probability of getting at least one head is 7/8.

3 0

2 years ago

Read 2 more answers

The diagram shows the sector of a circle with the centre O and radius 6cm.

cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = $\frac{\theta}{360}(\pi r^{2})$

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = $\frac{50}{360}(\pi )(6)^2$

= 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = $\frac{1}{2}(OP)(PN)$

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = $\frac{PN}{ON}$

PN = ONsin(25°)

= 6sin(25°)

= 2.536 cm²

cos(25°) = $\frac{OP}{ON}$

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

= 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

≈ 1.92 cm²

3 0

3 years ago

In this exercise, we estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the populat

DiKsa [7]

Answer:

the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

Step-by-step explanation:

From the given information:

Let consider y to represent the number of years after 1999

Then the population in time (y) can be expressed as:

P(y) = 9400y + 924900

The average annual income can be written as:

A(y) = 1400y + 30388

The total personal income = P(y) × A(y)

The rate at which the total personal income is rising is T'(y) :

T'(y) = P'(y) × A(y) + P(y) × A'(y)

T'(y) = (9400y + 924900)' (1400y + 30388) + (9400y + 924900) (1400y + 30388)'

T'(y) = 9400(1400y + 30388) + (9400y + 924900) 1400

Since in 1999 y =0

Then:

T'(0) = 9400(1400(0) + 30388) + (9400(0) + 924900) 1400

T'(0) = 9400(30388) + (924900)1400

T'(0) = $1,580,507,200 billion

Therefore; the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

8 0

3 years ago

Please help me im no good w math​

Please help me im no good w math