From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c

Mathematics

2 answers:

sergiy2304 [10]2 years ago

5 0

1:-

$\\ \rm\Rrightarrow 4a+b+c+9a-c$

$\\ \rm\Rrightarrow 4a+9a+b+c-c$

$\\ \rm\Rrightarrow 13a+b$

2:-

$\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)$

$\\ \rm\Rrightarrow 18a-b-c-14a+2b+c$

$\\ \rm\Rrightarrow 18a-14a-b+2b-c+c$

$\\ \rm\Rrightarrow 4a+b$

cricket20 [7]2 years ago

3 0

Answer:

-19c + 4b + 2c

Step-by-step explanation:

(4a + b + c + 9a - c) - (18a - b - c + 14a - 2b - c)

= (13a + b) - (32a - 3b - 2c)

= 13a + b - 32a + 3b + 2c

= -19c + 4b + 2c

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