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Morgarella [4.7K]
3 years ago
15

From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c

Mathematics
2 answers:
sergiy2304 [10]3 years ago
5 0

1:-

\\ \rm\Rrightarrow 4a+b+c+9a-c

\\ \rm\Rrightarrow 4a+9a+b+c-c

\\ \rm\Rrightarrow 13a+b

2:-

\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)

\\ \rm\Rrightarrow 18a-b-c-14a+2b+c

\\ \rm\Rrightarrow 18a-14a-b+2b-c+c

\\ \rm\Rrightarrow 4a+b

cricket20 [7]3 years ago
3 0

Answer:

-19c + 4b + 2c

Step-by-step explanation:

(4a + b + c + 9a - c) - (18a - b - c + 14a - 2b - c)

= (13a + b) - (32a - 3b - 2c)

= 13a + b - 32a + 3b + 2c

= -19c + 4b + 2c

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1/3 of the students left are Europeans

1/3 (1/2s) = 1/6s  are Europeans

The rest are Australians = 150

Students = Americans + Europeans + Australians

   s          =   1/2s          +    1/6s    + 150

Combine like terms

s    = 1/2*3/3 *s + 1/6s +150

s = 3/6s + 1/6s +150

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Subtract 4/6s from each side

s -4/6s = 150

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Multiply each side by 3

3* 1/3s = 150*3

s = 450

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A radio station has three types of promotional items; Cds, hats and flying disks. Cd's are worth $4.50, hats are worth $3.25, an
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\$200.25

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Cost of 1 CD's =\$4.50

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Station's cost for the promotional items is calculated as follows: \left[\begin{array}{ccc}4.50&3.25&1.25\end{array}\right] \left[\begin{array}{ccc}11\\26\\53\end{array}\right]=4.50(11)+3.25(26)+1.25(53)\\\\=49.5+84.5+66.25\\\\=\$200.25

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