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ANEK [815]
3 years ago
15

5x 3. + 4x2-9 2x+1 2x2+x-3

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

~Re-write the equation~

SOLVE:

5x(3)+4x (2-9)+(2x+1)+(2x2+x-3)

5(1)(3)=15

4(2-9)=8+36=44

2x+1=3

2x2+x-3:4(1)-3=1

15+44+3+1

ANSWER=63x

Step-by-step explanation:

I wasn't quite sure because of the way you wrote it but here's an answer!

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Return to the credit card scenario of Exercise 12 (Section 2.2), and let C be the event that the selected student has an America
Nadya [2.5K]

Answer:

A. P = 0.73

B. P(A∩B∩C') = 0.22

C. P(B/A) = 0.5

   P(A/B) = 0.75

D. P(A∩B/C) = 0.4

E. P(A∪B/C) = 0.85

Step-by-step explanation:

Let's call A the event that a student has a Visa card, B the event that a student has a MasterCard and C the event that a student has a American Express card. Additionally, let's call A' the event that a student hasn't a Visa card, B' the event that a student hasn't a MasterCard and C the event that a student hasn't a American Express card.

Then, with the given probabilities we can find the following probabilities:

P(A∩B∩C') = P(A∩B) - P(A∩B∩C) = 0.3 - 0.08 = 0.22

Where P(A∩B∩C') is the probability that a student has a Visa card and a Master Card but doesn't have a American Express, P(A∩B) is the probability that a student has a has a Visa card and a MasterCard and P(A∩B∩C) is the probability that a student has a Visa card, a MasterCard and a American Express card. At the same way, we can find:

P(A∩C∩B') = P(A∩C) - P(A∩B∩C) = 0.15 - 0.08 = 0.07

P(B∩C∩A') = P(B∩C) - P(A∩B∩C) = 0.1 - 0.08 = 0.02

P(A∩B'∩C') = P(A) - P(A∩B∩C') - P(A∩C∩B') - P(A∩B∩C)

                   = 0.6 - 0.22 - 0.07 - 0.08 = 0.23

P(B∩A'∩C') = P(B) - P(A∩B∩C') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.4 - 0.22 - 0.02 - 0.08 = 0.08

P(C∩A'∩A') = P(C) - P(A∩C∩B') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.2 - 0.07 - 0.02 - 0.08 = 0.03

A. the probability that the selected student has at least one of the three types of cards is calculated as:

P = P(A∩B∩C) + P(A∩B∩C') + P(A∩C∩B') + P(B∩C∩A') + P(A∩B'∩C') +              

     P(B∩A'∩C') + P(C∩A'∩A')

P = 0.08 + 0.22 + 0.07 + 0.02 + 0.23 + 0.08 + 0.03 = 0.73

B. The probability that the selected student has both a Visa card and a MasterCard but not an American Express card can be written as P(A∩B∩C') and it is equal to 0.22

C. P(B/A) is the probability that a student has a MasterCard given that he has a Visa Card. it is calculated as:

P(B/A) = P(A∩B)/P(A)

So, replacing values, we get:

P(B/A) = 0.3/0.6 = 0.5

At the same way, P(A/B) is the probability that a  student has a Visa Card given that he has a MasterCard. it is calculated as:

P(A/B) = P(A∩B)/P(B) = 0.3/0.4 = 0.75

D. If a selected student has an American Express card, the probability that she or he also has both a Visa card and a MasterCard is  written as P(A∩B/C), so it is calculated as:

P(A∩B/C) = P(A∩B∩C)/P(C) = 0.08/0.2 = 0.4

E. If a the selected student has an American Express card, the probability that she or he has at least one of the other two types of cards is written as P(A∪B/C) and it is calculated as:

P(A∪B/C) = P(A∪B∩C)/P(C)

Where P(A∪B∩C) = P(A∩B∩C)+P(B∩C∩A')+P(A∩C∩B')

So, P(A∪B∩C) = 0.08 + 0.07 + 0.02 = 0.17

Finally, P(A∪B/C) is:

P(A∪B/C) = 0.17/0.2 =0.85

4 0
3 years ago
Identify each matrix A such that A^2 has identical diagonal elements?
Maksim231197 [3]

Answer:

The correct matrices are:

Matrix:

7 1 5

1 5 7

5 7 1

all diagonal elements of A^2 are: 7^2 + 1^2 + 5^2

Matrix:

9   18  27

27 -9  18

18  27 9

all diagonal elements of A^2 are: 9^2 + 27*18 + 18*27   or (-9)^2

Matrix:

8 1 6

6 8 1

1 6 8

all diagonal elements of A^2 are: 8^2 + 6*1 + 1*6

6 0
3 years ago
Which is the solution set of 7y +1> 8y- 9?
fomenos

Answer:

y < 10 or (10, -∞)

Step-by-step explanation:

7y + 1 > 8y - 9

Simply get the y's on the right by subtracting 7y from both sides:

1 > y - 9

then adding 9 to both sides:

y < 10

or in interval notation:

(10, -∞)

7 0
2 years ago
*PLEASE ANSWER, DIFFICULT QUESTION*
Serjik [45]

Answer:

d.) simplify the expression inside the pipe symbols

5 0
3 years ago
15 more than three times a number is equal to 75<br> Also please do a step by step
Vlad [161]

Answer:

Step-by-step explanation:

3n+15=75

three times a number is 3n. +15 is 15 more.

3n+15=75  subtract 15 from both sides to get the 3n alone

3n=60 divide by 3 to get the n by itself

n=20

4 0
2 years ago
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