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ANEK [815]
3 years ago
15

5x 3. + 4x2-9 2x+1 2x2+x-3

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

~Re-write the equation~

SOLVE:

5x(3)+4x (2-9)+(2x+1)+(2x2+x-3)

5(1)(3)=15

4(2-9)=8+36=44

2x+1=3

2x2+x-3:4(1)-3=1

15+44+3+1

ANSWER=63x

Step-by-step explanation:

I wasn't quite sure because of the way you wrote it but here's an answer!

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7 0
3 years ago
How many computers must the AB Computer Company sell to break even? Let x be the number of computers.
maksim [4K]

You break even if you spend exactly as much as you gain. In other words, if the cost and the revenue are the same:

C(x)=R(x) \iff 145+0.25x=1.5x

Subtract 0.25 from both sides:

145=1.25x

Divide both sides by 1.25:

x=\dfrac{145}{1.25}=116

So, they must sell 116 computers to break even. If they sell less, they'll lose money. If they sell more, they'll start making profit.

4 0
3 years ago
Help me out would you please?
Sliva [168]

Answer:

7a-28

Step-by-step explanation:

To expand this simply multiply both pieces of the inside by 7.

7a - 28

5 0
3 years ago
Read 2 more answers
A group issimpleif it has no nontrivial proper normal subgroups. LetGbe a simple group of order168. How many elements of order 7
stepladder [879]

Answer:

6*8=48 groups with elements of order 7

Step-by-step explanation:

For this case the first step is discompose the number 168 in factors like this:

168 = 8*3*7= 2^3 *3*7

And for this case we can use the Sylow theorems, given by:

Let G a group of order p^{\alpha} m  where p is a prime number, with m\leq 1 and p not divide m then:

1) Syl (G) \neq \emptyset

2) All sylow p subgroups are conjugate in G

3) Any p subgroup of G is contained in a Sylow p subgroup

4) n(G) =1 mod p

Using these theorems we can see that 7 = 1 (mod7)

By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.

Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.

So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168

3 0
3 years ago
Find the sum of 136 + 212. Explain why you did or did not regroup.
Katyanochek1 [597]
Sum= 348. you didn't have to regroup because no number went over 10
8 0
3 years ago
Read 2 more answers
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