Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
Answer:
15/2r - 40; Distributive Property
Step-by-step explanation:
You can use the Distributive Property to multiply the 5 across the expression in the parentheses.
5(3/2r - 8)
5 × 3/2r = 15/2r
5 × -8 = -40
Combine.
15/2r - 40
Hope this helps!
Answer:
B
Step-by-step explanation:
4x + 11y = 3
11y = -4x + 3
y = -4/11x + 3/11
perp. 11/4
y - 7 = 11/4(x - 2)
y - 7 = 11/4x - 11/2
y -14/2= 11/4x - 11/2
y = 11/4x + 3/2
Answer:
50 is correct
Step-by-step explanation:
did my math but I know you need it quick so sorry for brief answer
Answer:
not a right triangle
Step-by-step explanation:
We can use the Pythagorean theorem to see if it is a right triangle
a^2 + b^2 = c^2
15^2 + 12^2 = 21^2
225 + 144 = 441
369 = 441
This is not true so it is not a right triangle
