Answer:
6 : 1
Step-by-step explanation:
Given the ratio
12 : 2 ( divide both parts by 2 )
= 6 : 1 ← in the form n : 1
15 js the base of the rectangle because you find the area by doing length times width
A nine can go into a 20 two whole times. After that, there's still
some room left in the 20, but it's only enough room for a 2.
Answer:
![y^2 + 8y + 16](https://tex.z-dn.net/?f=%20y%5E2%20%2B%208y%20%2B%2016%20)
Step-by-step explanation:
![(6y^2 + 2y + 5) - (5y^2 - 6y - 11) =](https://tex.z-dn.net/?f=%20%286y%5E2%20%2B%202y%20%2B%205%29%20-%20%285y%5E2%20-%206y%20-%2011%29%20%3D%20)
The first set of parentheses is unnecessary, so it can just be removed.
![= 6y^2 + 2y + 5 - (5y^2 - 6y - 11)](https://tex.z-dn.net/?f=%20%3D%206y%5E2%20%2B%202y%20%2B%205%20-%20%285y%5E2%20-%206y%20-%2011%29%20)
To remove the second set of parentheses, you must distribute the negative sign that is to its left. It changes every sign inside the parentheses.
![= 6y^2 + 2y + 5 - 5y^2 + 6y + 11](https://tex.z-dn.net/?f=%20%3D%206y%5E2%20%2B%202y%20%2B%205%20-%205y%5E2%20%2B%206y%20%2B%2011%20)
Now you combine like terms.
![= 6y^2 - 5y^2 + 2y + 6y + 5 + 11](https://tex.z-dn.net/?f=%20%3D%206y%5E2%20-%205y%5E2%20%2B%202y%20%2B%206y%20%2B%205%20%2B%2011%20)
![= y^2 + 8y + 16](https://tex.z-dn.net/?f=%20%3D%20y%5E2%20%2B%208y%20%2B%2016%20)
Only 3 is needed
Step-by-step explanation: