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Softa [21]
3 years ago
6

Please help, I’m confused

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0

Answer:

220/221

Step-by-step explanation:

cos math

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Step-by-step explanation:

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Solve the literal equation for x.<br> y=5x-rx-5
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Answer:

x = \frac{y+5}{(5-r)}

Step-by-step explanation:

Given the literal equation, y = 5x - rx - 5,

In order to solve for x, start by adding 5 on both sides of the equation:

y + 5 = 5x - rx - 5 + 5

y + 5 = 5x - rx

Next, factor out x from the right-hand side of the equation:

y + 5 = x(5 - r)

Finally, divide both sides by (5 - r) to isolate x:

\frac{y+5}{(5-r)} =  \frac{x(5 - r)}{(5-r)}

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3 years ago
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Ann increased the quantities of all the ingredients in a recipe by 60%, percent. She used 80 grams , of cheese. How much cheese
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The recipe originally required 50 grams of cheese.

Step-by-step explanation:

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Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of e
emmainna [20.7K]

This question is incomplete, the complete question is;

Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of equations in terms of x, y, z, and t.) The line passes through the point (3, 1, 2) and is parallel to the line given by x  = y = z.

Answer:

the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

Step-by-step explanation:

Given that;

line x = y = z and point ( 3, 1, 2 )

the given line can be written as;

[x-0 / 1] = [y-0 / 1] = [z-0 / 1]

if two lines are parallel directional ratios are equal.

so DIRECTIONAL RATIOS  of given line is ( 1, 1, 1 )

therefore required line is;

[x-3 / 1] = [y-1 / 1] = [z-2 / 1] = t

⇒ [x-3 / 1] = t

x = t+3

[y-1 / 1] = t

y = t+1

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z = t+2

Therefore the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

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