EMMMEERRRGENCYY

1 answer:

4 0

Okay!
10% of 55 is 5.5
(Butterfly method)
10/100 = n/55
10*55= 550
550/100= 5.50

30% of 900 is 270
30/100 = n/900
30*900 = 27000
27000/100 = 270

25% of 200 is 50
25/100 = n/200
25*200 = 5000
5000/100 = 50

20*4-30
80-30
50

(2*7)+12
14+ 12
26

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My math problem is 3n(squared) - 28 = -17n I have to factor this! So i would move the 17 over and make it 3n(squared) +17n - 28

wel

It's easier I think to take it and go "what can I add together than makes 17, yet multiplies to 28"
although, I don't think this is a perfect square, either

(x+7)(3x-4) = 0

heres the factored form, but I couldn't even begin to say how I got it, all I know is that it works

8 0

3 years ago

The table shows values for functions f(x) and g(x) .

Vadim26 [7]

Answer: x = -2 and x = -1

Explanation:

The solution of an equality is the set of values of the unknown for which both members are equal. In this case, the values of x for which the two functions are equal.

The table shows three values of x for which the outputs of both f(x) and g(x) are equal. Those values of x are the solutions of the equality f(x) = g(x).

Such points are:

(-2,4) and (-1,2).

Realize that means that for x = -2 and x = -1, the values of both functions f(x) and g(x) are the same.

So, according to the table, x = -2, and x = -1 are solutions to f(x) = g(x)

3 0

3 years ago

Read 2 more answers

Pls helpppppppppppppppppppp

Volgvan

The answer is 2 √2.

The problem can be simplified by changing the square roots to look like this:
√(8y/y)
Simplify within the square root and you get this:
√8
Factor √8:
√4 √2
Simplify √4:
2 √2

7 0

3 years ago

Daniel makes $4.25 per hour plus $2.15 for

eimsori [14]

Answer:

he made 6 deliveries.

subtract $4.25 from his total, $17.15. you get $12.9. then divide that by $2.15 and it gives you 6.

5 0

3 years ago

Find symmetric equations for the line of intersection of the planes. z = 4x − y − 13, z = 6x + 5y − 13

MArishka [77]

The intersection line of two planes is the cross product of the normal vectors of the two planes.

p1: z=4x-y-13 => 4x-y-z=13
p2: z=6x+5y-13 => 6x+5y-z=13
The corresponding normal vectors are:
n1=<4,-1,-1>
n2=<6,5,-1>

The direction vector of the intersection line is the cross product of the two normals,
vl=
i j k
4 -1 -1
6 5 -1
=<1+5, -6+4, 20+6>
=<6,-2,26>
We simplify the vector by reducing its length by half, i.e.
vl=<3,-1,13>

To find the equation of the line, we need to find a point on the intersection line.
Equate z: 4x-y-13=6x+5y-13 => 2x+6y=0 => x+3y=0.
If x=0, then y=0, z=-13 => line passes through (0,0,-13)

Proceed to find the equation of the line:
L: (0,0,-13)+t(3,-1,13)
Convert to symmetric form:
$\frac{x-0}{3}=\frac{y-0}{-1}=\frac{z-(-13)}{13}$
=>
$\frac{x}{3}=\frac{-y}{1}=\frac{z+13}{13}$

3 0

3 years ago