Answer: 54.8
Explanation:
Answer: 1 right angle
Answer:
l
999 V
Charge deposited on the capacitor
= current x time
= 2 x 10⁻³ A x 5 x 10⁻³
= 10⁻⁵ C
increase in volt = charge deposited / capacitance
10⁻⁵ / .1 x 10⁻⁶
= 10² V
= 100 V
voltage in the beginning = -1 V
voltage at the end
= -1 + 100
99 V .
D
15m/ s
i hope this helps
