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sammy [17]
3 years ago
12

Se coloca agua en un recipiente de aluminio y se pone a calentar en una estufa que le suministra 230 kj, lo cual hace que la tem

peratura aumente a 16°C. Si en las mismas condiciones a la misma cantidad de agua se le suministra el doble de energía ¿cual sería el aumento de su temperatura?
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

32 °C.

Explanation:

Hola.

En este caso, debemos entender que la relación entre el calor y la temperatura viene dada por:

Q=mCp\Delta T

De este modo, dado que estamos estudiando la misma sustancia (agua) con masa constante, la relación calor-temperatura es lineal y directamente proporcional, por tal razón, si se duplica el calor suministrado, la temperatura también será duplicada, de modo que:

\Delta T_{nuevo}=2*16\°C\\\\\Delta T_{nuevo}=32\°C

¡Saludos!

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a man exerts 700 newtons of force to move a piece of furniture 4 meters. if it takes him 2 seconds to move the furniture, how mu
dybincka [34]

                               Work = (force) x (distance)

The work he did:    Work = (700 N) x (4m)  =  2,800 joules

The rate at which
he did it (power):    Work/time =  2,800 joules/2 sec

                                                =  1,400  joules/sec

                                                =  1,400 watts

                                                =  1.877... horsepower (rounded)
 
6 0
3 years ago
Which of the following statements is false? Group of answer choices Light that is high in energy has a high frequency. The atomi
MArishka [77]

Answer:

The last statement is false.

Explanation:

Photons (Electromagnetic radiation) are released when electrons drop from a higher energy lever to a lower energy level. Therefore the opposite insinuated by the last statement is wrong.

4 0
3 years ago
I need the answer right now pls help me
yaroslaw [1]

The AREA of the shaded region is the moving object's displacement.

7 0
4 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 N . When the rock is totally i
sergeinik [125]

Answer:

Density of unknown liquid is 2047 kg/m^3

Explanation:

When rock is suspended in air then the weight of the rock is counter balanced by the tension force in the string

So here we have

T = mg = 43.8 N

now when the rock is immersed in water then the tension in the string is and buoyancy force due to water is counter balanced by the weight of the object

so here we have

T_1 + F_b = mg

31.3 + F_b = 43.8

F_b = 43.8 - 31.3 = 12.5 N

now we have

(1000)V(9.81) = 12.5

V = 1.27 \times 10^{-3} m^3

now when the rock is immersed into other liquid then we have

T_2 + F_b' = mg

18.3 + F_b' = 43.8

F_b' = 25.5 N

now we have

\rho(1.27 \times 10^{-3})(9.81) = 25.5

\rho = 2047 kg/m^3

4 0
3 years ago
Which applied force will allow a 7.65 kg block of ice to begin sliding on a sheet of ice? The block of ice has a kinetic coeffic
Anni [7]

Answer:

force for start moving is 7.49 N

force for moving constant velocity 2.25 N

Explanation:

given data

mass = 7.65 kg

kinetic coefficient of friction = 0.030

static coefficient of friction = 0.10

solution

we get here first weight of block of ice that is

weight of block of ice = mass  ×  g

weight of block of ice = 7.65 × 9.8 = 74.97 N

so here Ff = Fa

so for force for start moving is

Fa = weight × static coefficient of friction  

Fa = 74.97 × 0.10

Fa =  7.49 N

and

force for moving constant velocity is

Fa =  weight × kinetic coefficient of friction

Fa = 74.97 × 0.030

Fa = 2.25 N

7 0
4 years ago
Read 2 more answers
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