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sammy [17]
3 years ago
12

Se coloca agua en un recipiente de aluminio y se pone a calentar en una estufa que le suministra 230 kj, lo cual hace que la tem

peratura aumente a 16°C. Si en las mismas condiciones a la misma cantidad de agua se le suministra el doble de energía ¿cual sería el aumento de su temperatura?
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

32 °C.

Explanation:

Hola.

En este caso, debemos entender que la relación entre el calor y la temperatura viene dada por:

Q=mCp\Delta T

De este modo, dado que estamos estudiando la misma sustancia (agua) con masa constante, la relación calor-temperatura es lineal y directamente proporcional, por tal razón, si se duplica el calor suministrado, la temperatura también será duplicada, de modo que:

\Delta T_{nuevo}=2*16\°C\\\\\Delta T_{nuevo}=32\°C

¡Saludos!

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nikklg [1K]

Answer:

1)  ΔE = -800 J, 2) ΔE = 200 J, 3)  ΔE = -200 J, 4) ΔE = 800 J

Explanation:

For this exercise let's use the first law of thermodynamics

             

          ΔE = Q + W

Where we will apply this expression to several cases

1) output Q = 500 J and does work of W = 300 J.

The two processes involve an energy output

         ΔE = - 500 - 300

         ΔE = -800 J

Therefore, the internal energy of the gas decreases by this amount,

2) enter Q = 500J and do work of W = 300 J

         Positive heat is added and does negative work

         ΔE = 500 - 300

         ΔE = 200 J

3) they leave Q = 500 J and do (work on the gas) W = 300J

negative heat and positive work come out

          ΔE = -500 + 300

          ΔE = -200 J

4) heat enters Q = 500 J, work on gas W = 300 J

both positive

         ΔE = 500 + 300

         ΔE = 800 J

7 0
3 years ago
fingerprints left on a piece of glass such as a windowpane can show colored spectra like that from a diffraction grating. why?
charle [14.2K]

The skin oils from the finger will deposit on smooth surfaces in the pattern of the closely spaced ridges when the finger contacts them.

<h3>What is diffraction ?</h3>

The Huygens-Fresnel principle, which views each point in a propagating wave front as a collection of unique spherical wavelets, describes the diffraction phenomenon in classical physics. When a wave from a coherent source (such a laser) comes into contact with a slit or aperture that is roughly the same size as its wavelength, the characteristic bending pattern is most noticeable.

There are numerous closely spaced ridges and swirls on the skin of a fingertip. The skin oils from the finger will deposit on smooth surfaces in the pattern of the closely spaced ridges when the finger contacts them. In order to create a crude diffraction grating and create a coloured spectrum of the light travelling through or reflecting from the glass surface, open intervals between the lines of deposited oil can be used as slits.

To know more about Diffraction

brainly.com/question/12290582

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7 0
1 year ago
The collision and joining of crustal fragments to a continent is called continental _____.
astra-53 [7]
<h3><u>Answer;</u></h3>

Continental accretion

<h3><u>Explanation;</u></h3>
  • The collision and joining of crustal fragments to a continent is called the continental<em><u> </u></em><em><u>accretion</u></em><em><u>.</u></em>
  • <em><u>Accretion is the process through which materials such as sediment, volcanic arcs, or seamounts or blocks,  etc. are added to the tectonic plate or land mass.</u></em> Many astronomical bodies, such as stars, galaxies or planets are formed by this process.
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3 years ago
In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
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Answer:

D = -4/7 = - 0.57

C = 17/7 = 2.43

Explanation:

We have the following two equations:

3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)

First, we isolate C from equation (2):

2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)

using this value of C from equation (3) in equation (1):

3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}

<u>D = - 0.57</u>

Put this value in equation (3), we get:

C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C =  \frac{17}{7}\\

<u>C = 2.43</u>

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