Given:
Uniform distributed load with an intensity of W = 50 kN / m on an overhang beam.
We need to determine the maximum shear stress developed in the beam:
τ = F/A
Assuming the area of the beam is 100 m^2 with a length of 10 m.
τ = F/A
τ = W/l
τ = 50kN/m / 10 m
τ = 5kN/m^2
τ = 5000 N/ m^2<span />
'Universe' means 'Everything'. That is, all matter, all space, all time.
When distance<span> is increased the amount of </span>force<span> needed will depend on the </span>mass<span> of the object. </span>
